Answer:
is the rate constant for this reaction.
It will take
to concentration to reach 12.5% of its original value.
Explanation:
A decomposition reaction follows first order kinetics:
Half life of the reaction = 
Rate constant of the reaction = k
For first order reaction, half life and rate constant are linked with an expression :


is the rate constant for this reaction.
Initial concentration of reactant =
= x
Final concentration of reactant after time t =
= 12.5% of x = 0.125x
The integrated law of first order reaction :
![[A]=[A_o]\times e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-kt%7D)

t = 1,734.31 years =
It will take
to concentration to reach 12.5% of its original value.
Answer:
the answer is A
Explanation:
According to the law of conservation of energy or the first law thermodynamics energy neither be created nor destroyed, energy is transferred from one form to another form.
Answer:
The answer is B an open system allows energy and mass to move in and out of it
Hope it helps
a. 381.27 m/s
b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide
<h3>Further explanation</h3>
Given
T = 100 + 273 = 373 K
Required
a. the gas speedi
b. The rate of effusion comparison
Solution
a.
Average velocities of gases can be expressed as root-mean-square averages. (V rms)

R = gas constant, T = temperature, Mm = molar mass of the gas particles
From the question
R = 8,314 J / mol K
T = temperature
Mm = molar mass, kg / mol
Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

b. the effusion rates of two gases = the square root of the inverse of their molar masses:

M₁ = molar mass sulfur dioxide = 64
M₂ = molar mass nitrogen triodide = 395

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide
Answer:
The answer of the scientific STATEMENT is" Appears That Ants Live In Colonies."