Answer : The [α] for the solution is, -118.8
Explanation :
Enantiomeric excess : It is defined as the difference between the percentage major enantiomer and the percentage minor enantiomer.
Mathematically,
Given:
% major enantiomer = 86 %
% minor enantiomer = 14 %
Putting values in above equation, we get:
Now we have to calculate the [α] for the solution.
![[\alpha]=\text{Enantiomer excess}\times [\alpha]_{Pure}](https://tex.z-dn.net/?f=%5B%5Calpha%5D%3D%5Ctext%7BEnantiomer%20excess%7D%5Ctimes%20%5B%5Calpha%5D_%7BPure%7D)
![[\alpha]=0.72\times -165](https://tex.z-dn.net/?f=%5B%5Calpha%5D%3D0.72%5Ctimes%20-165)
![[\alpha]=-118.8](https://tex.z-dn.net/?f=%5B%5Calpha%5D%3D-118.8)
Thus, the [α] for the solution is, -118.8
300 ohms as you can add the individual resistances together
Answer:
It's D
Explanation:
Sorry for the late answer. Since the squirrel ran constant speed for 10 seconds and it ran 20 meters the first point would be at (10,20) then since it stopped to rest for 15 seconds the next point would be (25,20) finally since it ran another 30 meters for 15 more seconds the next point would be at (40,50). Sorry if the answer isn't the best, i'm bad at explaining ;w;
Nitrogen (around 78%), Oxygen (around 21%), and Argon (around 1%).
Hope this helps :)
