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nexus9112 [7]
3 years ago
6

Light is incident on the left face of an isosceles prism; with an apex angle of 49o, such that the light exiting the right face

is parallel to its surface.
What is the index of refraction of the prism, if the angle of incidence on the left face side is 19o to the normal of the face? Light is incident towards the apex.
Physics
2 answers:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

\mu = 1.645

Explanation:

By Snell's law we know at the left surface

\theta_i = 19^o

\theta_r = ?

\mu_1 = 1

\mu_2 = \mu

now we have

1 sin19 = \mu sin\theta_r

0.33 = \mu sin\theta_r

now on the other surface we know that

angle of incidence = \theta_r'

\theta_e = 90

so again we have

\mu sin\theta_r' = 1 sin90

so we have

\theta_r = sin^{-1}\frac{0.33}{\mu}

\theta_r' = sin^{-1}\frac{1}{\mu}

also we know that

\theta_r + \theta_r' = 49

sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49

By solving above equation we have

\mu = 1.645

Fynjy0 [20]3 years ago
3 0

Answer:

Explanation:

Cool

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Answer:

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If two objects at different temperatures are brought in contact with each other, energy is transferred from the hotter object (that is, the object with the greater temperature) to the colder (lower temperature) object, until both objects are at the same temperature. There is no net heat transfer once the temperatures are equal because the amount of heat transferred from one object to the other is the same as the amount of heat returned. One of the major effects of heat transfer is temperature change: Heating increases the temperature while cooling decreases it. Experiments show that the heat transferred to or from a substance depends on three factors—the change in the substance’s temperature, the mass of the substance, and certain physical properties related to the phase of the substance.

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Answer:

<h2>a) 50°</h2><h2>b) 40°</h2>

Explanation:

Check the complete diagram n the attachment below

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According to the diagram, the angle of reflection r₂ on M₂ is 90°-g where g is the angle of glance.

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According the second law of reflection, the angle of incidence = angle of reflection, therefore i₂ = r₂ = 50° (on M₂)

Also ∠OO₂O₁ =  ∠OO₁O₂ = 40° (angle of glance on M₁){alternate angle}

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Answer:

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