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nexus9112 [7]
3 years ago
6

Light is incident on the left face of an isosceles prism; with an apex angle of 49o, such that the light exiting the right face

is parallel to its surface.
What is the index of refraction of the prism, if the angle of incidence on the left face side is 19o to the normal of the face? Light is incident towards the apex.
Physics
2 answers:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

\mu = 1.645

Explanation:

By Snell's law we know at the left surface

\theta_i = 19^o

\theta_r = ?

\mu_1 = 1

\mu_2 = \mu

now we have

1 sin19 = \mu sin\theta_r

0.33 = \mu sin\theta_r

now on the other surface we know that

angle of incidence = \theta_r'

\theta_e = 90

so again we have

\mu sin\theta_r' = 1 sin90

so we have

\theta_r = sin^{-1}\frac{0.33}{\mu}

\theta_r' = sin^{-1}\frac{1}{\mu}

also we know that

\theta_r + \theta_r' = 49

sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49

By solving above equation we have

\mu = 1.645

Fynjy0 [20]3 years ago
3 0

Answer:

Explanation:

Cool

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5 0
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Read 2 more answers
Andy Petite pitches a 0.8 kg baseball with a velocity of 67 m/s. Josh Hamilton
kodGreya [7K]

The Impulse delivered to the baseball is 89 kgm/s.

To solve the problem above, we use the formula of impulse.

⇒ Formula:

  • I = m(v-u)................. Equation 1

Where:

  • I = Impulse delivered to the baseball
  • m = mass of the baseball
  • v = Final velocity of the baseball
  • u = initial speed of the baseball

From the question,

⇒ Given:

  • m = 0.8 kg
  • u = 67 m/s
  • v = -44 m/s

⇒ Substitute these values into equation 1

  • I = 0.8(-44-67)
  • I = 0.8(-111)
  • I = -88.8
  • I ≈ -89 kgm/s

Note: The negative tells that the impulse is in the same direction as the final velocity and therefore can be ignored.

Hence, The Impulse delivered to the baseball is 89 kgm/s.

Learn more about impulse here: brainly.com/question/7973509

7 0
2 years ago
IS
jarptica [38.1K]

Answer:

5.03

Explanation:

trust me

7 0
2 years ago
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