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earnstyle [38]
3 years ago
12

Anne adds granulated sugar to water and stirs it until all the sugar dissolves, leaving a sweet, transparent liquid. Under which

category should she classify that liquid?
a) solution
b) compound
c) suspension
d) colloid
Chemistry
2 answers:
krok68 [10]3 years ago
6 0

the answer should be a) solution , a solution is the term used for when two substances that is combined but does not chemically make a third substance .

almond37 [142]3 years ago
4 0
The best and most correct answer among the choices provided by your question is the first choice or letter A.

The resulting liquid is now classified as a solution.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Answer; chemical reaction

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All the following process lead to a decrease in salinity of seawater except for A. melting of sea Ice B. Precipitation C. runoff
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Evaporation is the only
8 0
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Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of 6.32 × 1014 Hz.
tester [92]

Answer:

474 nm or 4.74 x 10^2 nm

Explanation:

c = λv

c (speed of light) = 2.998 x 10^8 m/s

λ = ?

v = 6.32 × 1014 Hz = 6.32 × 1014 1/s

2.998 x 10^8 m/s = (λ)(6.32 × 10^14 1/s)

λ = (2.998 x 10^8 m/s) / (6.32 × 10^14 1/s)

λ = 4.74 x 10^-7 m

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7 0
2 years ago
A chemist must dilute 61.9 mL of 548. nM aqueous sodium carbonate (Na2CO3) solution until the concentration falls to 484. nM . H
maw [93]

Answer:

The final volume will be "70.08 mL".

Explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

     = 5.48\times 10^{-7} \ M

M2 = 484 nM

or,

      = 4.84\times 10^{-7} \ M  

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒ M1\times V1=M2\times V2

or,

⇒            V2=\frac{M1\times V1}{M2}

By substituting the values, we get

                    =\frac{5.48\times 10^{-7}\times 61.9}{4.84\times 10^{-7}}

                    =\frac{339.212}{4.84}

                    =70.08 \ mL

7 0
3 years ago
Cavendish’s name for hydrogen gas was "inflammable air." The word inflammable means "to burn. "Why did Cavendish use this name?
saul85 [17]
He used that name because if you lit hydrogen on fire it would catch. therefore, it was dangerous to be around. think of it as a kind of warning. :) hope that helps.
8 0
3 years ago
Read 2 more answers
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