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3 years ago

In the reactants there is a curvy arrow, what does the direction of the arrow indicate?

Chemistry

2 answers:

yanalaym [24]3 years ago

7 0

Answer:

Option C.

Because the cations give away an electron and the anions accept electrons

zysi [14]3 years ago

3 0

Answer: Option (C) is the correct answer.

Explanation:

When a curvy arrow is placed on the reactants then it shows that an electron is being transferred from one atom to another.

And, it is known that when donation or transfer of an electron occurs from one atom to another then it results in the formation of an ionic bond and the compound formed is known as ionic compound.

For example, sodium when chemically combines with chlorine atom then one valence electron is donated by sodium atom to the chlorine atom. This forms the ionic compound NaCl.

Thus, we can conclude that in the reactants there is a curvy arrow, the direction of the arrow indicate that the cations give away an electron and the anions accept electrons.

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Draw the best Lewis structure for NH3 by filling in the bonds, lone pairs, and formal charges. (Assign bonds, lone pairs, radica

kiruha [24]

Answer : The Lewis-dot structure of $NH_3$ is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $NH_3$

As we know that hydrogen has '1' valence electron and nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in $NH_3$ = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

Now we have to determine the formal charge for each atom.

Formula for formal charge :

$\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}$

$\text{Formal charge on N}=5-2-\frac{6}{2}=0$

$\text{Formal charge on }H_1=1-0-\frac{2}{2}=0$

$\text{Formal charge on }H_2=1-0-\frac{2}{2}=0$

$\text{Formal charge on }H_3=1-0-\frac{2}{2}=0$

Hence, the Lewis-dot structure of $NH_3$ is shown below.

3 0

3 years ago

Ignore the answer I have selected but please help!! Ty in advance, also please explain

weeeeeb [17]

Answer:

Iodine is most reactive because it is very close to having a "full shell" which is 8 electrons so they are "eager" to gain the last electron to became balanced, so that makes it the most reactive. Hope that helps:)

Explanation:

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Answer:

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