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3 years ago

11

In terms of absorption and reflection, describe why anobject

1 answer:

pishuonlain [190]3 years ago

4 0

Answer & Explanation:

Object are usually considered opaque (its neither transparent or translucent) unless stated otherwise and the color of an opaque object is determine by the color of the light its reflects.

White light comprises of seven constituent of color: red, orange, yellow, green, blue, indigo, violet.

When white light is shown on a red object, it reflects red color only and absorbs all the remaining six colors. Hence, it appears red to the human eye.

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Trace the changes that take place in a flower from gamete formation to fruit

enyata [817]

Answer:

The answer B is correct

Explanation:

The answer B is correct

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3 years ago

The complete combustion of a small wooden match produces approximately 512 cal of heat. How many kilojoules are produced? Expres

k0ka [10]

We have to covert 512 cal of heat in kilo joules.

As, 1 cal = 0.004184 kJ = 4.184 joules.

Therefore,

$512 \ cal = 512 \times 4.184 \ J = 2142.208 \ J \\\\\ = 2.142 \times 10 ^3 J = 2.142 \ kJ$

Thus, combustion of a small wooden match produces approximately ( in kilo joules ) is 2.142 kJ .

5 0

3 years ago

Why is it useful to know the net force?

galben [10]

Answer:

the object has a net force acting on it, it will accelerate the object will speed up, slow down, or change direction.

Explanation:

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3 years ago

Read 2 more answers

If you fired a rifle straight upwards at 1000 m/s, how far up will the bullet get?

nadya68 [22]

Answer:

h = 51020.40 meters

Explanation:

Speed of the rifle, v = 1000 m/s

Let h is the height gained by the bullet. It can be calculated using the conservation of energy as :

$\dfrac{1}{2}mv^2=mgh$

$h=\dfrac{v^2}{2g}$

$h=\dfrac{(1000\ m/s)^2}{2\times 9.8\ m/s^2}$

h = 51020.40 meters

So, the bullet will get up to a height of 51020.40 meters. Hence, this is the required solution.

4 0

3 years ago

In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6

Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

$\lambda = \dfrac{h}{mv}$

$1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}$

$v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}$

v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

$E = \dfrac{1}{2}mv^2$

$E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2$

E = 2.5 x 10⁻¹⁴ J

8 0

3 years ago