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TEA [102]
3 years ago
13

Plot points at (0, 0) and (3, 4). Draw a line through the points. What is the slope of your line?

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

4/3

Step-by-step explanation:

slope equation is y2-y1 over x2- x1. resulting in your slope of 4/3

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2^2 + (2√3)^2 = y^2<br><br> Please help!
IrinaK [193]

Answer:

y=4, -4

Step-by-step explanation:

2^2 + (2√3)^2 = y^2

4+ (2√3)^2 = y^2

y^2=4+12 (here we square the values inside bracket which turns 2 into 4 and when you square a square root it gets rid of the root so you are left with 3 which is multiplied to 4 and you get 12.)

y^2= 16

y=4, -4 (when you square root a positive value you get one positive and one negative answer because here (-4) x (-4) = 16 (because multiplying two negatives gives us a positive.

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3 years ago
Find the slope containing the points (5, 2) and (1, 6)
djverab [1.8K]
-1. Remember rise over run

4 0
3 years ago
PLEASE HELP!!!! Solve the equation. Check for extraneous solutions. Type your answers in the blanks. Show your work.
Licemer1 [7]
|4x+3|=9+2x  if we square both sides, we can eliminate the absolute values signs...

16x^2+24x+9=81+36x+4x^2  subtract the right side from both sides

12x^2-12x-72=0  now we can factor

12(x^2-x-6)=0

12(x^2+2x-3x-6)=0

12(x(x+2)-3(x+2)=0

12(x-3)(x+2)

So:

x= -2 or 3


5 0
3 years ago
In the diagram, PN is the perpendicular bisector of AB and is also the angle bisector of
Svet_ta [14]
The perpendicular bisector is a line segment that is drawn from a vertex of an angle to the midpoint of another line segment creating a right triangle or a 90° angle in the process. Suppose AB is the base segment of the triangle, therefore the perpendicular sector is also the angle bisector of the other angle of the triangle, supposedly angle C. Angle bisector is a line segment that divides the angle into two equal parts. Imagine a line drawn from the top vertex C extended down to the midpoint of line AB. That is the perpendicular and angle bisector.
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