Question

A 12.0-m wire with a mass of 145 g is under tension. A transverse wave, for which the frequency is 630 Hz, the wavelength is 0.50 m, and the amplitude is 2.0 mm, is propagating on the wire What is the maximum transverse acceleration of a point on a wire, in SI units?

Answer 1

Answer:

The maximum traverse acceleration is   $\alpha = 31346.095 m/s^2$

Explanation:

Generally the maximum transverse acceleration is mathematically represented as

                   $\alpha = w^2 A$

Where $w$ is the angular velocity which is mathematically evaluated as

                 $w = 2 \pi f$

Substituting the values given in the question

               $w = 2 * 3.142 * 630$

                   $= 3958.92 rad/s$

  A is the A is amplitude with a value of 2.0mm $= \frac{2}{1000} = 0.002m$

         Substituting this into the formula for maximum transverse acceleration

                              $\alpha = 3958.96^2 * 0.002$

                                  $= 31346.095 m/s^2$