Heat produced = -13588.956 kJ
<h3>Further explanation</h3>
Given
The reaction of combustion of Methane
CH4(g)+2O2(g)→CO2(g)+2H2O(g) ΔH∘rxn=−802.3kJ
271 g of CH4
Required
Heat produced
Solution
mol of 271 g CH₄ (MW=16 g/mol0
mol = mass : MW
mol = 271 : 16
mol = 16.9375
So Heat produced :
= mol x ΔH°rxn
= 16.9375 mol x −802.3kJ/mol = -13588.956 kJ
Answer:
105.9888 g/mol
Explanation:
The molar mass of sodium carbonate is 105.9888 g/mol (grams per mole)
Molar mass of C6H12O6 = 6x12 + 12x1 + 6x16 = 180g
SO mass of 1 mole of C6H12O6 = 180g
mass of 0.5 mole of C6H12O6 = 0.5 x180g = 90g
It always points towards the products.
