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goblinko [34]
3 years ago
5

Why is their no overall charge on atoms?

Chemistry
1 answer:
GarryVolchara [31]3 years ago
8 0
An atom contains protons, neutrons and electrons.
Protons have a positive charge (+1).
Neutrons have no charge (0)
Electrons have a negative charge (-1)

The number of protons and electrons is always the same and so the charges add up to make 0. Therefore there is no overall charge on atoms.
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Ventilator should be kept in our room give reasons of science ​
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Ventilators are provided in the rooms at the top of the roofs because if the air inside the room gets hot, the hot air rises up and flows through these ventilators and thus cool air remains at bottom. Thus ventilators maintain conventional currents to keep the air fresh in the room.

Explanation:

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4 years ago
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To see a RED object, all the light is absorbed except the Red and that is what we see as the color True False
Dafna11 [192]

Answer: True

Explanation:

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In addition, objects have pigments, which generally absorb more light than they reflect (they absorb certain wavelengths and reflect others). Therefore, the color that a given object seems to have depends on which parts of the visible electromagnetic spectrum are reflected and which parts are absorbed.  

In this sense, the colours we see are in fact the wavelengths that are reflected or transmitted from the object.  For example, a red object has that color because when it is illuminated whith white light, the pigments on this object abrsorb all the the wavelengths of the visible electromagnetic spectrum, except red. That is why red light is the only light that is reflected from the mentioned object.

7 0
3 years ago
Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow
andreyandreev [35.5K]

Explanation:

(a)  The given data is as follows.

              Pressure on top (P_{o}) = 140 bar = 1.4 \times 10^{7} Pa       (as 1 bar = 10^{5})

              Temperature = 15^{o}C = (15 + 273) K = 288 K

         Density of gas = \frac{PM}{ZRT}

                \frac{dP}{dZ} = \rho \times g

               \frac{dP}{dZ} = \int \frac{PM}{ZRT}

                \int_{P_{o}}^{P_{1}} \frac{dP}{dZ} = \frac{Mg}{ZRT} \int_{0}^{4700} dZ

           ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}

                              = 0.4548

                     P_{1} = P_{o} \times e^{0.4548}

                                 = 1.4 \times 10^{7} Pa \times 1.5797

                                 = 2.206 \times 10^{7} Pa

Hence, pressure at the natural gas-oil interface is 2.206 \times 10^{7} Pa.

(b)   At the bottom of the tank,

                 P_{2} = P_{1}  + \rho \times g \times h

                             = 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

                             = 309.8 \times 10^{5} Pa

                             = 309.8 bar

Hence, at the bottom of the well at 15^{o}C pressure is 309.8 bar.

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