Answer is: pressure of oxygen is 31,3 kPa.
The total pressure<span> of an ideal gas mixture is the sum of the </span>partial pressures<span> of the gases in the mixture.
p(mixture) = p(helium) + p(oxygen) + p(carbon dioxide).
p(oxygen) = p(mixture) - (p(helium) + p(carbon dioxide)).
p(oxygen) = 101,4 kPa - (68,7 kPa + 1,4 kPa).
p(oxygen) = 101,4 kPa - 70,1 kPa.
p(oxygen) = 31,3 kPa.
</span>
Answer:
The weights of all elements are always compared to the Carbon-12.
Explanation:
The weights of all elements are always compared to the Carbon-12 because the mass of carbon is 12 which is the exactly the sum of protons and neutrons.
Oxygen was also considered the standard for some time but later this stander was rejected because in natural O¹⁷ and O¹⁸ were also present and this create the two different atomic mass tables.
AMU:
Atomic mass unit is define as the 1/12 the mass of an atom of carbon-12.
C12 has six neutron and six protons in the nucleus.
This unit is used to express the masses of atoms. We know that masses of atoms are very small and we do not have any such type of balance that can measure very small quantity. So that is way we use this scale to measure small quantity. For example, according to this scale
relative atomic mass of hydrogen is 1.008 amu
relative atomic mass of oxygen is 15.999 amu
relative atomic mass of uranium is 238.0289 amu
relative atomic mass of chlorine is 35.453 amu
If there are no selections than i would say a thick atmosphere and an unusual large moon.<span />
Answer:
We need 0.095 moles of ethanol
Explanation:
Step 1: Data given
Number of moles water = 0.095 moles
Step 2: The balanced equation
CH3CH2OH + O2 ⇒ H2O + CH3COOH
Step 3: Calculate moles of ethanol
For 1 mol ethanol we need 1 mol oxygen to produce 1 mol water and 1 mol acetic acid
For 0.095 moles water, we need 0.095 moles ethanol and 0.095 moles oxygen
We need 0.095 moles of ethanol
Lipids and <span>They belong in class amphibia or known as amphibians Amphibians they fall into amphibians It is an amphibian in the Anura family amphibian</span>
