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Nezavi [6.7K]
3 years ago
12

Balance each equation by entering the correct coefficients.

Chemistry
1 answer:
natali 33 [55]3 years ago
6 0

Answer:

5SiO2 + 2CaC2 --> 5Si + 2CaO + 4CO2

4NH3 + 5O2 --> 4NO + 6H2O

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How many grams of NaOH are contained in 500 mL of a 0.80 M sodium hydroxide solution?
4vir4ik [10]

This is molarity: moles of solute/liters of solution. (Not molality)

1. Plug in what we know:

500 mL = 0.5 L

0.80 = moles/0.5

0.80*0.5 = moles

moles = 0.4

2. NaOH is given as 40 g/mole, so calculate the grams:

0.4 * 40 = 16 grams

answer: 16 grams

7 0
3 years ago
A sample of gas initially has a volume of 1.42 L at 293 K and 1.30 atm. What volume will the sample have if the pressure changes
worty [1.4K]

Answer:

1.35

Explanation:

5 0
3 years ago
Name the gas that the limewater in the flask is testing for.
enyata [817]

Answer:

Explanation:

Carbon dioxide is the answer I think.

Hope it helps...

4 0
3 years ago
For maleic acid, hoocch=chcooh, ka1 = 1.42  10–2 and ka2 = 8.57  10–7 . what is the concentration of maleate ion (–oocch=chcoo
uranmaximum [27]

ANSWER

Find the attachment

7 0
3 years ago
Read 2 more answers
In going from room temperature 25° to 35 the rate of a reaction doubles calculate the activation energy for the reaction
Pepsi [2]

Answer:

52.9 KJmol-1

Explanation:

From;

log(k2/k1) = Ea/2.303 * R (1/T1 - 1/T2)

The temperatures must be converted to Kelvin;

T1 = 25° C + 273 = 298 K

T2= 35°C + 273 = 308 K

R= gas constant = 8.314 JK-1mol-1

Substituting values;

log 2 = Ea/2.303 * 8.314 (1/298 - 1/308)

Ea = 52.9 KJmol-1

4 0
3 years ago
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