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Juliette [100K]
3 years ago
10

Exit When an object is charged either positively or negatively, what can be said about the electric field surrounding the object

?
A. It's neutral.
B. It increases with distance from the object.
C. It decreases with distance from the object.
D. It will automatically discharge once it builds up.
Physics
1 answer:
taurus [48]3 years ago
7 0
Believe the ANWSER is b or a
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The direction of rotation of Venus is _________ to the direction of all other planets.
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A - opposite



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3 years ago
A ball is rolling across the floor at a constant velocity. What is the value of the change in its kinetic energy, ΔEk?
Katyanochek1 [597]

B. When the ball is rolling across the floor at a constant velocity, the change in its kinetic energy is zero.

<h3>What is change in kinetic energy?</h3>

The change in kinetic energy of an object is the dereference between the final kinetic energy and the initial kinetic energy.

ΔK.E = K.Ef - K.Ei

ΔK.E = 0.5m(vf² - vi²)

where;

  • K.Ef is the final kinetic energy
  • K.Ei is the initial kinetic energy
  • vf is final velocity
  • vi is initial velocity

At constant velocity, the initial velocity and final velocity are equal.

ΔK.E = 0.5m(0) = 0

Thus, when the ball is rolling across the floor at a constant velocity, the change in its kinetic energy is zero.

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

5 0
2 years ago
When light enters a pair of glasses, it ______________ when it hits the glass
Natali [406]
The answer is it refracts 
5 0
4 years ago
Read 2 more answers
How is momentum conserved is a Newton's cradle when one steel ball hits the other
Vikentia [17]

Answer:

Newton's Cradle experiment perfectly demonstrates the law of conservation of momentum which states that in a closed system, momentum before the collision is equal to momentum after the collision of the system.

As the first ball swings in the air, it gains momentum. When it strikes the second ball, it loses momentum and second ball gains equal amount of momentum. The second ball transfers the momentum to third, then fourth and till the last. The last ball when gains the same momentum swings up in the air. This continues. This experiment is done in drag free condition. This means there is no loss of momentum or opposing forces present.


4 0
3 years ago
A 0.9 kg ball attached to a cord is whirled in a vertical circle of radius 2.5 m. Find the minimum speed needed at the top of th
lapo4ka [179]

Answer:

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

Explanation:

By the Principle of Energy Conservation we understand that the minimum speed needed by the ball is that speed such that maximum height reached is equal to the diameter of the vertical circle, that is:

K =U_{g} (1)

Where:

K - Translational kinetic energy, measured in joules.

U_{g} - Gravitational potential energy, measured in joules.

By definitions of translational kinetic and gravitational potential energies, we expand the equation above and clear the initial speed of the ball:

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g\cdot h

v = \sqrt{2\cdot g\cdot h} (2)

Where:

m - Mass, measured in kilograms.

v - Initial speed, measured in meters per second.

g - Gravitational acceleration, measured in meters per square second.

h - Maximum height of the ball, measured in meters.

If we know that g = 9.807\,\frac{m}{s^{2}} and h = 5\,m, then the initial speed of the ball is:

v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}

v\approx 9.903\,\frac{m}{s}

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

3 0
4 years ago
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