Answer:
increase in temperature of water is 10° C
Explanation:
Given data
pizza = 500 kcal = 500000 calories
cold water = 50 L
to find out
increase in temperature of water
solution
we know heat formula that is
heat = m × specific heat × Δt
here m is mass = 50000 gram and Δt is change in temperature
and specific heat = 1 cal / gram C
so put here all value and find Δt
500000 = 50000 × 1 × Δt
Δt = 10° C
so increase in temperature of water is 10° C
Answer:
528 liter.
Explanation:
Volume of the tank(cuboid) = l*b*h
But volume of the water = l*b*h
Where
l= length of the tank
b = width of the tank
h = the length from the bottom of the tank,
3.55 in to m,
0.09017m
Length of the water in the tank = 0.570 - 0.09017
= 0.47983 m.
Volume = 0.47983*0.710*1.55
= 0.528 m3.
1 m3 = 1000 liter.
0.528 m3 = 0.528*1000
= 528 liter
That’s really easy ask your teacher and also peace happy
Acceleration is measured in meters per second square.