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3 years ago

Identical rays of light in air are refracted upon entering three transparent materials:

Physics

1 answer:

aev [14]3 years ago

3 0

Answer:

Explanation:

for us to rank them we need to calculate the angle of refraction for the various materials. The angle of refraction is the angle between the refracted ray and the normal.

refractive index(n) = velocity of light in air/ velocity of light in medium

refractive index (n) = sini/sinr

lets equate the right side of both equations.

$\frac{sini}{sinr}=\frac{c}{velocity of light in medium}$

we will assume 30 degree as the angle of incidence for all materials.

(a) water

$\frac{sin30}{sinr}=\frac{c}{0.75c}$

sinr = 0.75c/c *sin30

sinr = 0.375

r= arcsin0.375

r=22.02°

(b) ethyl alcohol

$\frac{sin30}{sinr}=\frac{c}{0.7c}$

sinr = 0.7c/c *sin30

sinr = 0.35

r= arcsin0.35

r=20.49°

$\frac{sin30}{sinr}=\frac{c}{0.6c}$

sinr = 0.6c/c *sin30

sinr = 0.3

r= arcsin0.35

r=17.46°

it is observed that the angle of refraction decreases as the velocity of light in glass decreases.

ranking the materials according to how much the light ray bends toward the normal, from most bending to least bending we have;

Crown glass > ethyl alcohol> water

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A rugby player runs with the ball directly toward his opponent's goal, along the positive direction of an x axis. He can legally

Over [174]

Answer:

minimum angle is 128.69°

Explanation:

given data

player velocity with respect ground v1 = 3.5 m/s

ball velocity with respect himself v2 = 5.6 m/s

to find out

smallest angle

solution

we know ball velocity with respect field will be

ball velocity = v1 +v2

ball velocity = 3.5 + 5.6 = 9.1m/s

we consider angle that player hit ball is θ

then by as per figure triangle

cosθ = $\frac{v1}{v2}$

cosθ = $\frac{3.5}{5.6}$

θ = 51.31

so minimum angle is 180 - 51.31 = 128.69°

6 0

3 years ago

In the Millikan oil drop experiment the measured charge of any single droplet was always a whole number multiple of -1.60 x 10-1

BaLLatris [955]

Answer:

Number of electrons, n = 6

Explanation:

Total charge in a single droplet, $q=-9.6\times 10^{-19}\ C$

The measured charge of any single droplet, $e=-1.6\times 10^{-19}\ C$

Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :

$q=ne$

$n=\dfrac{q}{e}$

$n=\dfrac{-9.6\times 10^{-19}}{-1.6\times 10^{-19}}$

n = 6

So, there are 6 electrons contained within the drop. Hence, this is the required solution.

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3 years ago

A 1-megabit computer memory chip contains many 27 fF capacitors. Each capacitor has a plate area of 3.09 × 10−11 m 2 . Determine

valentina_108 [34]

Answer:

Plate separation of each capacitor is 101.132 °A

Explanation:

The formula to calculate the capacitance in empty space as a function of distance (square parallel plates) is:

$C=\epsilon_{0}\frac{Area}{distance}$

clearing for distance:

$distance=\epsilon_0 \frac{Area}{Capacitance} \\\\\epsilon_0=8.8542(10)^{-12}C^2/Nm\\\\Area=3.09(10)^{-11}m^2\\Capacitance=27(10)^{-15}F\\\\Replacing\\\\distance=\frac{8.8542(10)^{-12}*3.09(10)^{-11}}{27(10)^{-15}} =1.0133(10)^{-8}m\\\\In A\\distance= 101.132 A$

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3 years ago

Suppose a 1300 kg car is traveling around a circular curve in a road at a constant

Scrat [10]

Answer:

F = 4212 N

Explanation:

Given that,

Mass of a car, m = 1300 kg

Speed of car on the road is 9 m/s

Radius of curve, r = 25 m

We need to find the magnitude of the unbalanced force that steers the car out of its natural straight- line path. The force is called centripetal force. It can be given by :

$F=\dfrac{mv^2}{r}\\\\F=\dfrac{1300\times 9^2}{25}\\\\F=4212\ N$

So, the force has a magnitude of 4212 N

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2 years ago

A 10 Kg ball is rolling at 2.5 m/s. It is then hit from behind with a bat that puts a 300 N force on the ball for a quick .3 sec

vazorg [7]

Answer: g. gg g rfrcdv

Explanation:

vfv g bygyb

7 0

3 years ago