<span>The force of static friction F equals the coefficient of friction u times the normal force N the object exerts on the surface: F = uN. N is the centripetal force of the wall on the people; N = ma_N, where m is the mass of the people and a_N is the centripetal acceleration.
The people will not slip down if F is greater than the force of gravitation: F = uma_N > mg, or u > g/a_N.
a_N is the velocity v of the people squared divided by the radius of the room r: a_N = v^2/r.
The circumference of the room is 2 pi r = 28.3 m. So v = 28.3 * 0.8 m/sec = 22.6 m/sec.
So a_N = 114 m/sec^2.
g = 9.81 m/sec^2, so u must be at least 9.81/114 = 0.086.</span>
Theoritically
the body moving with uniform velocity has acceleration zero.
Mathmatically,
u=3m/s
v=3m/s (since body is moving with uniform velocity)
a= v-u/t
3-3/t
0/t
0m/s.s
a una velocidad de
22 m/s, quien lo golpea y devuelve en la misma
dirección con una velocidad de 14 m/s. Si el
tiempo de contacto del balón con la jugadora es
de 0,03 s, ¿con qué fuerza golpeó la jugadora el
balón?
21 Una bala de 0,8 g, está en la recámara de un rifl e
cuando se g
Answer:
W = 285.62 N
Explanation:
It is given that,
Mass of Jessica is 55 kg
Slope of the hill is 32 degrees
We need to find the component of her weight that is along her direction of motion.
The component along her direction of motion is shown in attached figure. It means
So, the component of her weight that is along her direction of motion is 285.62 N.
Answer:
Explanation:
given,
s = 400- 16 t²
we know,
Velocity of an object is defined as the change in displacement per unit change in time.
velocity an also be return as
Hence, instantaneous velocity function given by
To calculate instantaneous velocity, you need to insert value of time.
ex, instantaneous velocity at t = 4 s
v = -32 x 4 = -128 m/s.
