Answer:
It is true. a) 0.25 mol
Explanation:
<em>Hello </em><em>there?</em>
To begin solving this problem, you have to write down the chemical equation and make sure it is well balanced.
The chemical equation is;
3Mg(s) + N2(g) => Mg3N2(s)
1 mole of Mg = 24g
We have 18g of Magnesium (Mg) reacting with Nitrogen gas (N2)
From our equation,
Mole ratio = 3 : 1, (Mg : N2)
1 mol Mg = 24g
x mol Mg = 18g
x mol Mg = (18/24) = 0.75 mol Mg
But mole ratio = 3 : 1 (Mg : N2)
This means that 3 => 0.75 mol Mg
What about ratio 1 of N2?
N2 = (0.75 mol ÷ 3)/1
= 0.25 mol N2
<em>I </em><em>hope</em><em> </em><em>this </em><em>helps</em><em> </em><em>you </em><em>to </em><em>understand</em><em> </em><em>better</em><em>.</em><em> </em><em>Ha</em><em>v</em><em>e </em><em>a </em><em>nice </em><em>studies.</em><em> </em><em />
Total internal energy change is equals to -44.83kJ
Q=-73.2kJ (negative sign indicates that heat was released by the system),
P= 50.0atm
ΔU= Q + W, FIRST LAW OF THERMODYNAMICS..........(1)
ΔV= Final volume - initial volume= 2.00 litre - 7.60litre= -5.60litre
work done by the system (w)= -PΔV
w= -(50.0×(-5.60)) atm×litre= 280atm litre
1 atm litre= 101.325J
w= 280 ×101.325 J= 28,371J
1kJ=1000J,
w=28.37KJ,
so putting in the values in equation (1)...
energy change(ΔU) = -73.2 kJ + 28.37 kJ
= - 44.83 kJ
Answer: 0.529 atm
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 0.998 atm
= final pressure of gas = ?
= initial volume of gas = 2 L
= final volume of gas = 3.5 L
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
Thus the pressure if it is brought to a higher altitude where it now occupies 3.5 L and is at 12.0 °C is 0.529 atm
