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Mariulka [41]
3 years ago
10

Elect the correct equations that show that when a 3.0-kg book is lifted 2.6 m its increase in gravitational potential energy is

78 j .
Physics
1 answer:
grigory [225]3 years ago
5 0
The increase in gravitational potential energy for an object of mass m is given by
\Delta U = mg \Delta h
where \Delta h is the increase in altitude of the object.

In our problem, m=3.0 kg, \Delta h= 2.6 m and g=10 m/s^2 (approximated value), so we have
\Delta U = mg\Delta h=(3.0 kg)(10 m/s^2)(2.6 m)=78 J
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A single slit of width 0.3 mm is illuminated by a mercury light of wavelength 254 nm. Find the intensity at an 11° angle to the
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Answer:

The  the intensity at an 11° angle to the axis in terms of the intensity of the central maximum is  

   I_c = \frac{I}{I_o}  =8.48 *10^{-8}

Explanation:

From the question we are told that

   The  width of the slit is  D  =  0.3 \ mm =  0.3 *10^{-3} \ m

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  I_c = \frac{I}{I_o}  = [ \frac{sin (708.1)  }{(708.1)}] ^2

   I_c = \frac{I}{I_o}  =8.48 *10^{-8}

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