What does light do in the photoelectric effect?
1 answer:
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<u>Answer:</u> The cell voltage of the given reaction is 1.86 V
<u>Explanation:</u>
The given chemical equation follows:
<u>Oxidation half reaction:</u> ( × 2)
<u>Reduction half reaction:</u> ( × 3)
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
To calculate the EMF of the cell, we use the Nernst equation, which is:
where,
= electrode potential of the cell = ? V
= standard electrode potential of the cell = +1.82 V
n = number of electrons exchanged = 2
R = Gas constant = 8.314 J/mol Kl
T = temperature =
F = Faraday's constant = 96500
Putting values in above equation, we get:
Hence, the cell voltage of the given reaction is 1.86 V