Answer:
Tp/Te = 2
Therefore, the orbital period of the planet is twice that of the earth's orbital period.
Explanation:
The orbital period of a planet around a star can be expressed mathematically as;
T = 2π√(r^3)/(Gm)
Where;
r = radius of orbit
G = gravitational constant
m = mass of the star
Given;
Let R represent radius of earth orbit and r the radius of planet orbit,
Let M represent the mass of sun and m the mass of the star.
r = 4R
m = 16M
For earth;
Te = 2π√(R^3)/(GM)
For planet;
Tp = 2π√(r^3)/(Gm)
Substituting the given values;
Tp = 2π√((4R)^3)/(16GM) = 2π√(64R^3)/(16GM)
Tp = 2π√(4R^3)/(GM)
Tp = 2 × 2π√(R^3)/(GM)
So,
Tp/Te = (2 × 2π√(R^3)/(GM))/( 2π√(R^3)/(GM))
Tp/Te = 2
Therefore, the orbital period of the planet is twice that of the earth's orbital period.
Answer:
0.98°
Explanation:
First we find the refracting angle of orange in water
Which is given as
စr= sin^-1. ( 1.456 sin60°/1.33)
= 71.2°
Then that of violet in water
စv=sin^-1. ( 1.468sin60°/1.342)
= 72.3°
So angle between boths colours is the difference
71.2- 72.3= 0.98°
I THINK THIS IS THOUGHTS AND FEELINGS
Answer:
A ping pong ball
Explanation:
It has the lightest weight among the rest
The direction of magnetic field is south-east and the magnitude is
× 
.
Here, the magnitude of CD and BC will be cancelled, as they both are in the opposite direction and equal to each other.
the magnitude, towards the diagonal AC will result in CP, which is the direction of the electric field.
magnitude of electric field can be defined as :- The force per charge on the test charge is a straight forward way to define the size of the electric field.
To find the magnitude of the electric field use the formula
inserting the values,
× 
× 
× 
/ 
× N/C
Learn more about calculating magnitude of the electric field at one corner here:-
brainly.com/question/14922532
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