Answer:
a. an increase in the mass on the spring.
Explanation:
T = 2π/ω = 2π/√(k/m) = 2π√(m/k)
2π is a constant
as m is in the numerator, increasing mass will increase the period.
Answer:
Explanation:
Current in a wire is 120mA
I = 120mA = 120 × 10^-3 A
I = 0.12 A
If the voltage applied at across the wire is tripled
From ohms law
V=IR
R = V / I
Since R is constant
Then,
V / I = K
Then, we can say
V / I = V' / I'
Given that,
Initially
V = V and I = 120mA
Then, V' = 3V and I' =?
So,
V / I = V' / I'
V / 120 = 3V / I'
Cross multiply
V × I' = 120 × 3V
Divide both sides by V
I' = 120 × 3V / V
I' = 360mA
So, the current in the wire when the voltage was tripled is 360mA, the current was also tripled
Same formula as the last question. x = vt + (1/2)at^2. In this case, v = 0, t = 12, and a = 2.0. Plug in the values and solve for x (which is change in position)
x = (0)(12) + (1/2)(2.0)(12^2)
x = (1/2)(2.0)(144)
x = (1)(144)
x = 144
So the car will travel 144 meters in 12 seconds.
Answer:
The strength of the electric field is 2.258 x 10⁸ N/C
Explanation:
Potential energy = -p*ECosθ
where;
d is the dipole moment
E is the electric field
θ is the angle of inclination
→When the water molecules is perpendicular to the field, θ =90° and potential energy = p*ECosθ = d*ECos0 = 0
Total potential energy = 0 + 1.40×10⁻²¹J, since it is 1.40×10⁻²¹J more
→When the water molecules is aligned to the field, θ =0°
potential energy = -p*ECosθ
dipole moment, p = 6.2×10⁻³⁰Cm
= -(6.2×10⁻³⁰)*(E) Cos0
0 + 1.40×10⁻²¹ J = -(6.2×10⁻³⁰)*(E),
E = (1.40×10⁻²¹ J)/(6.2×10⁻³⁰)
E = 2.258 x 10⁸ N/C
Therefore, the strength of the electric field is 2.258 x 10⁸ N/C
