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Anarel [89]
3 years ago
8

Using a rope that will snap if the tension in it exceeds 356 N, you need to lower a bundle of old roofing material weighing 478

N from a point 7.50 m above the ground. (a) What magnitude of the bundle's acceleration will put the rope on the verge of snapping? (b) At that acceleration, with what speed would the bundle hit the ground?
Physics
1 answer:
klasskru [66]3 years ago
5 0

Answer:

a) 2.5 m/s²

b) 6.12 m/s

Explanation:

Tension of rope = T = 356N

Weight of material = W = 478 N

Distance from the ground = s = 7.5 m

Acceleration due to gravity = g = 9.81 m/s²

Mass of material = m = 478/9.81 = 48.72

Final velocity before the bundle hits the ground = v

Initial velocity = u = 0

Acceleration experienced by the material when being lowered = a

a) W-T = ma

⇒478-356 = 48.72×a

\Rightarrow \frac{122}{48.72} = a

⇒a = 2.5 m/s²

∴ Acceleration achieved by the material is 2.5 m/s²

b) v²-u² = 2as

⇒v²-0 = 2×2.5×7.5

⇒v² = 37.5

⇒v = 6.12 m/s

∴ Velocity of the material before hitting the ground is 6.12 m/s

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Answer:

a. an increase in the mass on the spring.

Explanation:

T = 2π/ω = 2π/√(k/m) = 2π√(m/k)

2π is a constant

as m is in the numerator, increasing mass will increase the period.

6 0
3 years ago
The current in the wires of a circuit is 120.0 milliamps.If the voltage impressed across the ends of the circuit where tripled(w
ivanzaharov [21]

Answer:

Explanation:

Current in a wire is 120mA

I = 120mA = 120 × 10^-3 A

I = 0.12 A

If the voltage applied at across the wire is tripled

From ohms law

V=IR

R = V / I

Since R is constant

Then,

V / I = K

Then, we can say

V / I = V' / I'

Given that,

Initially

V = V and I = 120mA

Then, V' = 3V and I' =?

So,

V / I = V' / I'

V / 120 = 3V / I'

Cross multiply

V × I' = 120 × 3V

Divide both sides by V

I' = 120 × 3V / V

I' = 360mA

So, the current in the wire when the voltage was tripled is 360mA, the current was also tripled

3 0
4 years ago
in coal-fired power plants, coal is burned to produce ____________________, which is then used to turn a turbine.
crimeas [40]
The answer is STEAM.
6 0
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A car, starting from rest, accelerates in a straight-line path at a constant rate of 2.0 m/s2. How far will the car travel in 12
Kryger [21]
Same formula as the last question. x = vt + (1/2)at^2. In this case, v = 0, t = 12, and a = 2.0. Plug in the values and solve for x (which is change in position) x = (0)(12) + (1/2)(2.0)(12^2) x = (1/2)(2.0)(144) x = (1)(144) x = 144 So the car will travel 144 meters in 12 seconds.
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A water molecule perpendicular to an electric field has 1.40×10−21 J more potential energy than a water molecule aligned with th
vesna_86 [32]

Answer:

The strength of the electric field is 2.258 x 10⁸ N/C

Explanation:

Potential energy = -p*ECosθ

where;

d is the dipole moment

E is the electric field  

θ is the angle of inclination

→When the water molecules is perpendicular to the field, θ =90° and potential energy = p*ECosθ = d*ECos0 = 0

Total potential energy = 0 + 1.40×10⁻²¹J, since it is 1.40×10⁻²¹J more

→When the water molecules is aligned to the field, θ =0°

potential energy = -p*ECosθ

dipole moment, p = 6.2×10⁻³⁰Cm

                            = -(6.2×10⁻³⁰)*(E) Cos0

0 + 1.40×10⁻²¹ J = -(6.2×10⁻³⁰)*(E),

E = (1.40×10⁻²¹ J)/(6.2×10⁻³⁰)

E = 2.258 x 10⁸ N/C

Therefore, the strength of the electric field is 2.258 x 10⁸ N/C

3 0
3 years ago
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