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MariettaO [177]
3 years ago
8

I need to find x in #9 and w in #10

Mathematics
1 answer:
elena-s [515]3 years ago
6 0

Step-by-step explanation:

9. 131+106+67+x=360

237+67+x=360

304+x=360

x=56

10. 90+90+146+w=360

180+146+w=360

326+w=360

w=34

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You have ​$95 in your bank account. Each week you plan to deposit ​$9 from your allowance and ​$10 from your paycheck. The equat
kotykmax [81]

Answer:

7 weeks

Step-by-step explanation:

b​=95+(10+9​)w

Combine like terms

b​=95+(19​)w

Let b = 220

220 = 95 + 19w

Subtract 95 from each side

220-95 = 19w

125 = 19w

Divide each side by 19

125/19 = w

6.578947368

Round up

After 7 week

8 0
3 years ago
Please help me with some Algebra 2. Last stretch of the trimester and it’s 3:13AM. It’s my own fault for getting myself into thi
son4ous [18]

Answer:

A. 23+(6-1)x-3

B. 93

Step-by-step explanation:

a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference

6th row = 23 + (6 - 1) x -3

            = 23 + (5) x -3

            = 23 + (-15)

            = 8 - number of boxes in the top row.

b) Sum = N/2[2F + (N - 1) x D]

            = 6/2[2*23 + (6 - 1) x -3]

             = 3  [46  +    (5) x -3 ]

             = 3  [46  +      -15 ]

             = 3  [ 31 ]

             = 93 - total number of boxes in the entire display.

Hope this helps! Its 3:25 AM for me too so I know how you feel.

5 0
3 years ago
1 4th plus 5 8th equals
Finger [1]
These two have different denominators, so you find the least common multiple. This problem goes to be 2/8+5/8, which equals 7/8。
8 0
3 years ago
Simplify 4 to the 7th over 5 squared all raised to the 3rd power.
Radda [10]
First write out your original equation.
{(\frac{ {4}^{7} }{ {5}^{2} } ) }^{3}
Then use the law of exponents(power of a power) to simplify.
\frac{ {4}^{21} }{ {5}^{6} }
(Multiply the numerator and denominator exponents by the outside power.)

The answer is 4 to the 21st over 5 to the 6th.
6 0
3 years ago
Use the formula v = u + at to find the velocity when the initial velocity is 3 m/s the acceleration is 1.5 m/s the time is 7 s
vichka [17]

<em>answer \\ 13.5 \: m/s \\ given \\ initial \: velocity(u) =  \: 3 \: m/s \\ acceleration(a) = 1.5 \: m/s ^2\\ time(t) = 7 \: second \\ now \\ v = u  + at \\ or \: v = 3 + 1.5 \times 7 \\  \: or \: v = 3 + 10.5 \\ v = 13.5 \: m/s \\ hope \: it \: helps</em>

4 0
3 years ago
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