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gizmo_the_mogwai [7]
3 years ago
15

A stretch spring has an elastic potential energy of 35 J when it is stretched 0.54m. What is the spring constant of the spring?

Physics
1 answer:
AlekseyPX3 years ago
5 0

Answer:

240.1 N/m

Explanation:

Applying the formula for the potential energy stored in a stretched spring,

E = 1/2ke².................... Equation 1

Where E = potential energy, k = spring constant, e = extension.

make k the subject of the equation,

k = 2E/e².................. Equation 2

Given: E = 35 J, e = 0.54 m

Substitute into equation 2

k = 2(35)/0.54²

k = 70/0.2916

k = 240.1 N/m.

Hence the spring constant of the spring is 240.1 N/m

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Complete Question

How many turns are in its secondary coil, if its input voltage is 120 V and the primary coil has 210 turns.

The output from the secondary coil is  12 V

Answer:

The value  is  N_s  =  21 \  turns

Explanation:

From the equation we are told that

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