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gizmo_the_mogwai [7]
4 years ago
15

A stretch spring has an elastic potential energy of 35 J when it is stretched 0.54m. What is the spring constant of the spring?

Physics
1 answer:
AlekseyPX4 years ago
5 0

Answer:

240.1 N/m

Explanation:

Applying the formula for the potential energy stored in a stretched spring,

E = 1/2ke².................... Equation 1

Where E = potential energy, k = spring constant, e = extension.

make k the subject of the equation,

k = 2E/e².................. Equation 2

Given: E = 35 J, e = 0.54 m

Substitute into equation 2

k = 2(35)/0.54²

k = 70/0.2916

k = 240.1 N/m.

Hence the spring constant of the spring is 240.1 N/m

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A man walks 400 m in the direction 45° north of east. Represent this vector graphically by
Marrrta [24]

Answer:

Explanation:

Coordinate system is one that describe the location of an object in a given plane. It implies the use of axes (coordinates) and points.

Given that the man in the question walks 400 m due north of east. The cardinal points can be used in this case, with the north and east cardinals as the required axis.

scale = \frac{length on drawing}{original length}

         = \frac{10}{400}

         = \frac{1}{40}

scale = 1:40

This is a reduced scale which implies that 1 cm on the drawing is equal to 40 m on the original length.

The man's direction is 45^{o} north of east.

The graphical drawing of the vector is herewith attached to this answer.

5 0
3 years ago
What is the main difference between macroscopic kinetic energy in a motion and microscopic kinetic energy of individual molecule
labwork [276]

Answer:

Explained

Explanation:

1.The macroscopic form of kinetic energy is organized whereas the microscopic kinetic energy disorganized form of energy.

2.Observing macroscopic kinetic energy is easier than the microscopic energy.

3. All macroscopic kinetic energy can be converted to useful work whereas microscopic kinetic energy can not be.

4. Macroscopic kinetic energy is possessed  by moving objects whereas microscopic objects possessed by the virtue of motion, rotation, vibrations of atoms in substance.

Wind energy is macroscopic energy as it can be harnessed to produce electricity and perform some useful work. And discussed above useful work can only be performed using macroscopic kinetic energy.

8 0
3 years ago
Can you help me I am in trouble plz help ​
kupik [55]

Answer:

A velocity

B acceleration

C ms^-2

6 0
3 years ago
A 2 kilogram mass is lifted 4 meters above the ground what is the change it gravitational energy
lianna [129]

Answer:

78.4 J

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its location in the gravitational field.

The change in gravitational potential energy of an object is given by:

\Delta U=mg\Delta h

where:

m is the mass of the object

g=9.8 m/s^2 is the acceleration due to gravity

\Delta h is the change in height of the object

For the mass in  this problem, we have:

m = 2 kg is the mass

\Delta h = 4 m is the change in height

So, its change in gravitational energy is:

\Delta U=(2)(9.8)(4)=78.4 J

6 0
3 years ago
A football player runs at 8m/s and plows into a 80kg referee standing on the field causing the referee to fly forward at 5m/s. I
madreJ [45]

The topic here is momentum.

When a collision is said to be elastic, it means that the colliding objects now travel at their own new, indivual and distinct velocities, often in different directions.

So we write that as,

(mass of football player x velocity of football player) + (mass of referee x velocity of referee) = (mass of football player x velocity of football player) + (mass of referee x velocity of referee)

(M × 8) + (80 × 0) = (M× 0) + (80 × 5)

8M = 400

M = 50 kg

4 0
3 years ago
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