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3 years ago

Calculate the force on an object that has a mass of 12kg and an acceleration of 4m/s2.

Physics

2 answers:

Eduardwww [97]3 years ago

6 0

48 kgm/s2. Sorry if I'm wrong

iVinArrow [24]3 years ago

4 0

By Newton's second law of motion, we know that the resultant force acting on a body is directly proportional to the mass of the body and directly proportional to its acceleration. In system international (SI) units, the value of the constant of proportionality constant is 1. Therefore, the equation for Newton's second law of motion becomes: F = ma, where F is the resultant force, m is the mass and a is the acceleration of the object. Substituting the values of m and a into this formula, we get the result: F = 12 x 4 = 48. The SI unit for force is the Newton; therefore, the answer is 48 Newtons.

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You drive your car in a straight line at 15 m/s for 10 kilometers, then at 25 m/s for another 10 kilometers.

Vikki [24]

Answer:

A) Average speed = 18.75 m/s

B) More time is spent at 15 m/s than at 25 m/s.

Explanation:

Let the first distance be d1 and the second distance be d2.

We are given;

d1 = 10 km = 10000 m

d2 = 10 km = 10000 m

Speed; v1 = 15 m/s

Speed; v2 = 25 m/s

Now, the formula for distance is; Distance = speed x time

Thus:

d1 = v1 x t1

t1 = d1/v1 = 10000/15 = 666.67 seconds

Also,

d2 = v2 x t2

t2 = d2/v2 = 10000/25 = 400 seconds

Average speed = total distance/total time = (10000 + 10000)/(666.67 + 400) = 18.75 m/s

From earlier, since t1 = 666.67 seconds and t2 = 400 seconds, then;

More time at 15 m/s than at 25 m/s.

5 0

3 years ago

What is the acceptable level for chlorine

Katena32 [7]

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8 0

3 years ago

What does the term Hubble time mean in cosmology, and what is the current best calculation for the Hubble time?

balu736 [363]

Hubble time in cosmology means the estimated age of the universe and the best calculation for it is T=1/H, where H is the Hubble constant

4 0

3 years ago

A Meteorite Strikes On October 9, 1992, a 27-pound meteorite struck a car in Peekskill, NY, leaving a dent 22 cm deep in the tru

vagabundo [1.1K]

Answer:

Acceleration of the meteorite, $a=-38409.09\ m/s^2$

Explanation:

It is given that,

A Meteorite after striking struck a car, v = 0

Initial speed of the Meteorite, u = 130 m/s

Distance covered by Meteorite, s = 22 cm = 0.22 m

We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{-(130)^2}{2\times 0.22}$

$a=-38409.09\ m/s^2$

So, the deceleration of the Meteorite is $-38409.09\ m/s^2$ . Hence, this is the required solution.

7 0

3 years ago

A(n) 55.5 g ball is dropped from a height of 53.6 cm above a spring of negligible mass. The ball compresses the spring to a maxi

Serggg [28]

Answer:

The spring force constant is $k=243\ \frac{N}{m}$ .

Explanation:

We are told the mass of the ball is $m=0.0555\ kg$ , the height above the spring where the ball is dropped is $h=0.536\ m$ , the length the ball compresses the spring is $d=0.04897\ m$ and the acceleration of gravity is $9.8\ \frac{m}{s^{2}}$ .

We will consider the initial moment to be when the ball is dropped and the final moment to be when the ball stops, compressing the spring. We supose that there is no friction so the initial mechanical energy $E_{mi}$ is equal to the final mechanical energy $E_{mf}$ :

$E_{mf}=E_{mi}$

Initially there is only gravitational potential energy because the force of the spring isn't present and the speed is zero. In the final moment there is only elastic potential energy because the height is zero and the ball has stopped. So we have that:

$\frac{1}{2}kd^{2}=mgh$

If we manipulate the equation we have that:

$k=\frac{2mgh}{d^{2} }$

$k=\frac{2\ 0.0555\ kg\ 9.8\frac{m}{s^{2}}\ 0.536\ m}{(0.04897)^{2}m^{2}}$

$k=\frac{0.58306\ \frac{kgm^{2}}{s^{2}}}{2.398x10^{-3}m^{2}}$

$k=243\ \frac{N}{m}$

5 0

3 years ago