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Sedaia [141]
3 years ago
14

How fast can Usain Bolt run if it takes him 9.9 s to run 100m?​

Physics
2 answers:
Arte-miy333 [17]3 years ago
8 0

Answer:

27.8 mph

Explanation:

May I have brainliest please? :)

inysia [295]3 years ago
7 0
The formula for speed is speed=distance/time therefore it would be speed=100/9.9 which would make his speed 10.1010101m/s
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When a 0.350-kg package is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The package is now di
AleksandrR [38]

To solve the problem it is necessary to use the concepts related to the calculation of periods by means of a spring constant.

We know that by Hooke's law

F=kx

Where,

k = Spring constant

x = Displacement

Re-arrange to find k,

k= \frac{F}{x}

k= \frac{mg}{x}

k= \frac{(0.35)(9.8)}{12*10^{-2}}

k = 28.58N/m

Perioricity in an elastic body is defined by

T = 2\pi \sqrt{\frac{m}{k}}

Where,

m = Mass

k = Spring constant

T = 2\pi \sqrt{\frac{0.35}{28.58}}

T = 0.685s

Therefore the period of the oscillations is 0.685s

4 0
3 years ago
An object weighs 30 N on Earth. A second object weighs 30 N on the Moon. Which has the greater mass?
andreev551 [17]

Answer:

The object on earth, because earth has a bigger amount of gravity than how much the moon has.

Explanation:

6 0
3 years ago
Please help me with Part B & help me correct the rest of the questions
AleksAgata [21]

Answer:

Magnetic activity and sunspots are in a proportional relationship.

Explanation:

From the graph, as one increases, so does the other, thus we describe the relationship as proportional.

Other than that, all of your other answers seem correct.

5 0
3 years ago
Consider a thin, spherical shell of radius 14.5 cm with a total charge of 29.5 µC distributed uniformly on its surface. (a) Find
ra1l [238]

Answer:

10.0     zero, by Gauss' Law the symmetrical distribution will produce no internal electric fields

21.5     E = k Q / R^2     behaves as if all charge were at center

E = 9 E9 * 29.5 E-6 / .215^2 = 5.74E6 N/C

8 0
3 years ago
Calculate the electric field strength required to just support an oil drop of mass
Ray Of Light [21]

Answer:

E= 3.06 \times 10^{-17} N/C

Explanation:

As we know that the oil drop experiment tells us the balancing the gravitational force by electrostatic force.

So ,

Electrostatic force = Gravitational force

qE=mg

Here , q is charge , E is electric field , m is mass and g is gravity.

so,

E=\frac{mg}{q}

Insert values from question,

E=\frac{10^{-2}kg \times 9.8 m/s^{2}}{3.2 \times 10^{-19}C}

or

E= 3.06 \times 10^{-17} N/C

This is the required value of electric field.

3 0
3 years ago
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