The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
<em>"Your question is not complete, it seems to be missing the following information;"</em>
the specific heat capacity of the metal is 0.45 J/g⁰C.
The given parameters;
- <em>mass of water, </em>
<em> = 45 g</em> - <em>final temperature of the water, </em>
<em> = 22 ⁰C</em> - <em>mass of the metal, m = 8.5 g</em>
- <em>initial temperature of the metal, t = 82 ⁰C.</em>
- <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>
The initial temperature of the water will be calculated by applying the principle of conservation of energy;
<em>heat gained by water = heat lost by metal</em>


where;
<em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>
<em />
<em>Substitute the given values;</em>
45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)
4142.16 - 188.28t = 240.98
188.28t = 4142.16 - 240.98
188.28t = 3901.18

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
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Answer:
Liquids in a form of mixture has less weight as compared to sum of all liquid's weight due to release of gases.
The combined weights of several liquids mixed in an open flask be less than the sum of all the weights of the liquids because when the reaction occurs new products are formed and also some gases which releases in the atmosphere.
These gases also contribute in the weight of the product so when it is released the weight of the mixture of liquids are less than the sum of the weights of all liquids so we can conclude that liquids in a form of mixture has less weight as compared to sum of all liquid's weight.
Explanation:
Answer:
I don't know if this right or wrong but i think it is predecessor
Explanation:
maybe that is right
Answer:
Yes
Explanation:
It is balanced because On both sides there are 4 hydrogen atoms and 2 oxygen atoms, or in this case, 2 molecular hydrogens and 1 molecular oxygen, which made hydric acid, aka dihydrogen monoxide, or universally, as water.