1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maxonik [38]
3 years ago
11

Which has a greater amount of particles, 1.00 mole of hydrogen (H) or 1.00 moles of oxygen(0)?

Chemistry
1 answer:
Bas_tet [7]3 years ago
7 0

Answer:

Both have the same amount of particles.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ particles.

This implies that 1 mole of Hydrogen contains 6.02×10²³ particles. Also, 1 mole of oxygen contains 6.02×10²³ particles.

Thus, 1 mole of Hydrogen and 1 mole of oxygen contains the same number of particles.

You might be interested in
................ is the organic molecule that is the main energy source for cell processes and is made with the energy released
hoa [83]

Answer:

ATP

Explanation:

it is made by breaking glucose down

5 0
3 years ago
Read 2 more answers
1. The heat absorbed when ice melts can
zmey [24]
4 a joule is the answer
3 0
3 years ago
Hello guys i wanted to ask if anyone could check my answers please :) 10 points
arlik [135]
The first answer is C, condensation is a physical process and the others are chemical.

The second answer is B, it doesn't change depending on location (the answer you chose)

The third answer is A.

The fourth answer is B. Temperature is an intensive property.

No explanations for the ones you got correct.
7 0
3 years ago
Read 2 more answers
Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005 g sample of menthol is comb
Bogdan [553]

<u>Answer:</u> The molecular formula for the menthol is C_{10}H_{20}O

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.2829g

Mass of H_2O=0.1159g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.2829 g of carbon dioxide, \frac{12}{44}\times 0.2829=0.077g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.1159 g of water, \frac{2}{18}\times 0.1159=0.0129g of hydrogen will be contained.

  • Mass of oxygen in the compound = (0.1005) - (0.077 + 0.0129) = 0.0106 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.077g}{12g/mole}=0.0064moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0129g}{1g/mole}=0.0129moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.0106g}{16g/mole}=0.00066moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00066 moles.

For Carbon = \frac{0.0064}{0.00066}=9.69\approx 10

For Hydrogen  = \frac{0.0129}{0.00064}=19.54\approx 20

For Oxygen  = \frac{0.00066}{0.00066}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 10 : 20 : 1

Hence, the empirical formula for the given compound is C_{10}H_{20}O_1=C_{10}H_{20}O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 156.27 g/mol

Mass of empirical formula = 156 g/mol

Putting values in above equation, we get:

n=\frac{156.27g/mol}{156g/mol}=1

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 10)}H_{(1\times 20)}O_{(1\times 1)}=C_{10}H_{20}O

Thus, the molecular formula for the menthol is C_{10}H_{20}O

4 0
3 years ago
Read 2 more answers
Rate at which a chemical substance tends to undergo a chemical reaction
kifflom [539]
Reactivity is the name your looking for I believe.
6 0
3 years ago
Read 2 more answers
Other questions:
  • A sample of gas in a sealed container (fixed volume) is heated from room temperature to 80.0°C.
    5·1 answer
  • Is a substance that a filter can seperate into two parts a mixture or a pure substance?
    14·1 answer
  • What volume of gold would be equal in mass to a piece of copper with a volume of 101 ml? the density of gold is 19.3 g/ml; the d
    10·2 answers
  • Explain why water collects in the beaker but not ink
    12·1 answer
  • If you had a substance that water will not dissolve, then which of the following compounds would you choose to dissolve this sub
    13·1 answer
  • How were the Great Lakes formed?
    6·1 answer
  • Choose the products that complete the reaction. The chemical equation may not be balanced.
    14·2 answers
  • What is the mass of 2 moles of 238U?
    11·1 answer
  • Joan performed a shadow puppet play for her younger brother by shining a flashlight on paper cutouts behind a curtain. What happ
    12·1 answer
  • What is the oxidation number of bromine in the BrO3- ion?<br>​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!