Explanation:
q = mCΔT
where q is heat,
m is mass,
C is specific heat capacity,
and ΔT is temperature change.
For the first ball:
2500 J = (100 g) C (90°C − 25°C)
C = 0.385 J/g/°C
For the second ball:
5000 J = (200 g) C (90°C − 25°C)
C = 0.385 J/g/°C
The two metals have the same specific heat, and are likely the same metal (possibly copper or zinc).
the perpendicular component will be = Wy
Wy = w * cos 42.34 = 48.11 N x cos 42.34 = 35.54 N
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Answer:
0.8J
Explanation:
Given parameters:
Force = 20N
Compression = 0.08m
Unknown:
Spring constant = ?
Elastic potential energy = ?
Solution:
To solve this problem, we use the expression below:
F = k e
F is the force
k is the spring constant
e is the compression
20 = k x 0.08
k = 250N/m
Elastic potential energy;
EPE =
k e² =
x 250 x 0.08²
Elastic potential energy = 0.8J
Answer:
the heat absorbed by the block of copper is 74368.476J
Explanation:
Hello!
To solve this problem use the first law of thermodynamics that states that the heat applied to a system is the difference between the initial and final energy considering that the mass and the specific heat do not change so we can infer the following equation
Q=mCp(T2-T1)
Where
Q=heat
m=mass=2.3kg
Cp=0.092 kcal/(kg C)=384.93J/kgK
T2=Final temperatura= 90C
T1= initial temperature=6 C
solving

the heat absorbed by the block of copper is 74368.476J