It’s C I hope it helps you
Answer:
The smallest angular velocity is 4.42 rad/s and the largest angular velocity is 13.15 rad/s for the toast to hit and then topple to be butter-side down
Explanation:
62 cm = 0.62 m
Knowing that the vertical distance traveled is s = 0.62 m and gravitational acceleration is g = 9.81 m/s2, we can calculate the time of falling
If there's only 0.36s to rotate, and for the toast to hit and then topple to be butter-side down, then the angle of rotation must be between 90 and 270 degrees (Suppose that it starts with butter up and it rotates less than 1 revolution, or 360 degrees):
In other words (and units):
rad
As :
rad/s
rad/s
rad/s
So the smallest angular velocity is 4.42 rad/s and the largest angular velocity is 13.15 rad/s for the toast to hit and then topple to be butter-side down
Answer:
First option
Explanation:
If the ball is running in a circular motion then its velocity <em>v</em> will be tangency to the circular path.
In this problem the centripetal force that allows the circular movement is the tension <em>T</em> of the rope to which the ball is tied, if the child releases the rope then this tension becomes equal to zero and the circular movement is interrupted.
As the speed <em>v</em> of the ball is always tangential to the circumference at any point of the same, then at the instant in which the rope is released, the ball will follow the same trajectory that it had at that moment, that is, tangential to the circumference.
Observe the attached image.
Therefore the answe is: tangent to the circle