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inn [45]
3 years ago
14

What is buoyant force on the ball? Question 9 on student exploration: Archimedes Princable

Physics
1 answer:
mariarad [96]3 years ago
3 0
Mass of the displaced material. In water it would be the mass of the water that the volume of the ball displaces.
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A student, standing on a scale in an elevator at rest, sees that his weight is 840 N. As the elevator rises, his weight increase
ololo11 [35]

As per FBD while its accelerating upwards

we can say that

F_n - mg = ma

here normal force is given as

F_n = 1050 N

W = 840 N

now mass is given as

m(9.8) = 840

m = 85.7 kg

now we will have

1050 - 840 = 85.7 \times a

a = 2.45 m/s^2

Now while accelerating downwards we can say by FBD

mg - F_n = ma

again plug in all values

840 - 588 = 85.7 \times a

a = 2.94 m/s^2

5 0
3 years ago
Which of the following is not a vector quantity?
baherus [9]

Answer: The answer is density

3 0
3 years ago
A floating ice block is pushed through a displacement d = (13.5 m)i + (-14.3 m)j along a straight embankment by rushing water, w
fredd [130]

To solve this problem, we are going to use the formula for work which is Fd where x and y are measured separately.

 

X direction: W = 13.5 x 230 = 3105 Joules

Y direction: W = -14.3 x -165 = 2360 Joules

So the total work is getting the sum of the two: 3105 + 2360 = 5465 Joules

7 0
3 years ago
A truck starts off 151 miles directly north from the city of Hartville. It travels due east at a speed of 41 miles per hour. Aft
Bess [88]

Answer:

9.51

Explanation:

The distance s is given by:

s(t) = \sqrt{151^2 + (vt)^2}

The change in distance is given by the time derivative of s:

\frac{ds}{dt} = \frac{v^2t}{\sqrt{151^2 + (vt)^2}}

For the time t you solve the equation of distance x for time:

x = vt => t = \frac{x}{v}

Plugging in for t:

\frac{ds}{dt}(t=\frac{x}{v})=\frac{vx }{\sqrt{151^2 + x^2}}=9.51

6 0
3 years ago
Question 9 of 10
mixer [17]

Answer:

I believe the correct answer is B..<u>" 1 "</u>

Explanation:

hope it helps! ;)

8 0
2 years ago
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