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inn [45]
4 years ago
14

What is buoyant force on the ball? Question 9 on student exploration: Archimedes Princable

Physics
1 answer:
mariarad [96]4 years ago
3 0
Mass of the displaced material. In water it would be the mass of the water that the volume of the ball displaces.
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The mass of the rock is 1220 kg. It had 400 J of potential energy when it rolled down the hill. calculate the heihht.
Sauron [17]

potential is equal to mgh

we know that mass = 1220 kg

g=9.8 0r 10

400=1220*9.8*x

400=11956x

x=400/11956

5 0
3 years ago
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Which are uses of fiber optics? Check all that apply.
RideAnS [48]

Answer:

Transmission of telephone signals

Explanation:

Fiber optics are used for the transmission of telephone signals.

4 0
4 years ago
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It has been claimed that an insect called the froghopper (Philaenus spumarius) is the best jumper in the animal kingdom. This in
Vladimir [108]

Answer:

v=4m/s

Explanation:

The formulas for accelerated motion are:

v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}

We can derive the formula v^2=v_0^2+2ad from them.

We have:

v-v_0=at\\t=\frac{v-v_0}{a}

And substitute:

x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}\\2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2

Where in the first step of the last row we just multiplied everything by 2a. Since x-x_0 is the displacement d, we have proved that v^2=v_0^2+2ad

We use then our values to calculate the final velocity when starting from rest, traveling a distance 0.002m with acceleration 4000 m/s^2:

v=\sqrt{v_0^2+2ad}=\sqrt{2(4000m/s^2)(0.002m)}=4m/s

7 0
3 years ago
Mug<br><br> xx nbbbbnbebe <br> lzu bbt here ju
konstantin123 [22]

Answer:

and a dumb person would say "what's the question" or "I don't get it"

8 0
3 years ago
What is the potential energy of a 150 kg diver standing on a diving board that is 10 m high? The potential energy is J
iris [78.8K]

The formula for potential energy would be PE = mgh Where: m is the mass; g is the acceleration due to gravity, and h would be height. So plugging in the data: PE = 150kg × 9.8 m/s^2 × 10m = 14700 Joules would be the potential energy for this problem. <span>
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5 0
4 years ago
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