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pochemuha
1 year ago
5

If the volume of the original sample in Part A ( P1 = 242 torr , V1 = 27.0 L ) changes to 80.0 L , without a change in the tempe

rature or moles of gas molecules, what is the new pressure, P2 ? Express your answer with the appropriate units.
Chemistry
1 answer:
Brrunno [24]1 year ago
3 0

The new pressure is 81.675 torr

Since temperature and moles are held constant, we use Boyle's Law:

A gas law known as Boyle's law asserts that a gas's pressure is inversely proportional to its volume when it is held at a fixed temperature and of a given mass.

To put it another way, as long as the temperature and volume of the gas remain constant, the pressure and volume of the gas are inversely proportional to one another.

The Anglo-Irish chemist Robert Boyle proposed Boyle's law in the year 1662.

P1V1=P2V2. Simply plug in your values. The units can remain in torr. Converting to atmospheres is not needed.

(242 torr)(27.0 L)=P2(80.0 L)

P2=[(242)(27)]/80 = 81.675 torr

Hence The new pressure is 81.675 torr

Learn more about Boyle's Law here

brainly.com/question/26040104

#SPJ4

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Solve these problems like weighted averages:

The first one:

Multiply the masses (isotope numbers) by the decimal form of the percentage. Add them

0.076 (6) + 0.924 (7) = 6.924


The second one:

0.2 (10) + 0.8 (11) = 10.8


If you think about it, these answers make sense. 6.924 is much closer to 7 than to 6 (since there's a lot more lithium-7 than there is lithium-6). 10.8 is closer to 11 than to 10.


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3 years ago
An ideal gas sample is confined to 3.0 L and kept at 27 °C. If the temperature is raised to 77 °C and the initial pressure was 1
Nadusha1986 [10]

The gas is confined in 3.0 L container ( rigid container) ⇒ the volume remains constant when the temperature is increased from from 27oC to 77oC and therefore V1=V2 .

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2 years ago
Both the National Fire Academy and Iowa formulas calculate the flow requirement for structures that are __________ percent invol
emmainna [20.7K]

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Explanation:

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2 years ago
The absorbance (????)(A) of a solution is defined as ????=log10(????0????) A=log10⁡(I0I) where ????0I0 is the incident‑light int
bulgar [2K]

Answer:

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

Explanation:

Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times c\times l

where,

A = absorbance of solution

c = concentration of solution

\epsilon = Molar absorption coefficient

l = path length

I_o = incident light

I = transmitted light

Given :

l = 1 cm, c = 1 mg/mL ,\epsilon = 15,000 M^{-1}cm^{-1}

Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol

(1 Da = 1 g/mol)

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A= 15,000 M^{-1}cm^{-1}\times 5.6179\times 10^{-5} mol/L\times 1 cm

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3 years ago
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The answer is -1. 2 subtraction signs next to each other for an addition sign
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