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CaHeK987 [17]
2 years ago
13

In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the

first light source has a wavelength of 640 nm. Two different interference patterns are observed. If the 10th order bright fringe from the first light source coincides with the 12th order bright fringe from the second light source, what is the wavelength of the light coming from the second monochromatic light source
Physics
1 answer:
PtichkaEL [24]2 years ago
8 0

Answer:

533.33 nm

Explanation:

Since dsinθ = mλ  for each slit, where m = order of slit and λ = wavelength of light. Let m' = 10 th order fringe of the first slit of wavelength of light, λ = 640 nm and m"= 12 th order fringe of the second slight of wavelength of light, λ'.

Since the fringes coincide,

m'λ = m"λ'

λ' = m'λ/m"

= 10 × 640 nm/12

= 6400 nm/12

= 533.33 nm

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A circular saw blade with radius 0.175 m starts from rest and turns in a vertical plane with a constant angular acceleration of
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Answer:

The distance the piece travel in horizontally axis is

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Explanation:

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a= 2.0 \frac{rev}{s^{2} } = 2.0(2\pi )  = 4.0\pi \frac{rev}{s^{2} }

d=d_{i}+vo*t+\frac{1}{2}*a*t^{2} \\ di=0\\vo=0\\d=\frac{1}{2}*a*t^{2}\\t=\sqrt{\frac{2*d}{a}}\\t=\sqrt{\frac{2*310 rad}{4\frac{rad}{s^{2}}}} \\t=12.449

w=a*t\\w=4\frac{rad}{s^{2}}*12.449s\\ w=49.79 \frac{rad}{s}

Now the angular velocity is the blade speed so:

V=w*r\\V=49.79 \frac{rad}{s}*0.175m\\V=8.7 \frac{m}{s}

assuming no air friction effects affect blade piece:

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t=\sqrt{\frac{2*h}{g}}\\t=\sqrt{\frac{2*0.820m}{9.8\frac{m}{s^{2} } }}\\t=0.409s

Now is the same time the piece travel horizontally

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6 0
3 years ago
2) what is altitude?
Ronch [10]
2) b) The height above the surface of the earth

3) b) air pressure differences that make air rise or sink

4) a) TC (I'm not sure about this)

5) I don't know this one. Sorry :(

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5 0
3 years ago
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Answer:

The distance from harvest mouse to the leaf is 4.74 m.

Explanation:

Given that,

Intensity = -10 dB

Distance = 1.5 m

We need to calculate the power of intensity

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P=I_{0}A

P=I_{0}\times4\pi r^2

Put the value into the formula

P=1.0\times10^{-12}\times4\pi\times(1.5)^2

P=28.27\times10^{-12}\ W/m^2

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Using formula of minimum intensity

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A=4\pi r^2

Put the value into the formula

282.7=4\pi\times r^2

r^2=\dfrac{282.7}{4\pi}

r=\sqrt{\dfrac{282.7}{4\pi}}

r=4.74\ m

Hence, The distance from harvest mouse to the leaf is 4.74 m.

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