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2 years ago

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In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the

first light source has a wavelength of 640 nm. Two different interference patterns are observed. If the 10th order bright fringe from the first light source coincides with the 12th order bright fringe from the second light source, what is the wavelength of the light coming from the second monochromatic light source

1 answer:

PtichkaEL [24]2 years ago

8 0

Answer:

533.33 nm

Explanation:

Since dsinθ = mλ for each slit, where m = order of slit and λ = wavelength of light. Let m' = 10 th order fringe of the first slit of wavelength of light, λ = 640 nm and m"= 12 th order fringe of the second slight of wavelength of light, λ'.

Since the fringes coincide,

m'λ = m"λ'

λ' = m'λ/m"

= 10 × 640 nm/12

= 6400 nm/12

= 533.33 nm

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We must be careful to the signs of s, u and a. Taking upward as positive direction, we have:

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- a (acceleration) negative, since it is downward: so a= g = -9.8 m/s^2 (acceleration of gravity)

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where again, we must be careful to the signs of the various quantities:

- u (initial velocity) positive, since it is upward: +15.5 m/s

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$-105 = 5.40 t -4.9t^2\\4.9t^2 -5.40 t-105=0$

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