True hope this helps, <span>Nictheuse !</span>
Answer:
The normal force the seat exerted on the driver is 125 N.
Explanation:
Given;
mass of the car, m = 2000 kg
speed of the car, u = 100 km/h = 27.78 m/s
radius of curvature of the hill, r = 100 m
mass of the driver, = 60 kg
The centripetal force of the driver at top of the hill is given as;

where;
Fc is the centripetal force
is downward force due to weight of the driver
is upward or normal force on the drive

Therefore, the normal force the seat exerted on the driver is 125 N.
B 0.4 m should be correct if not it is A
Answer:
The value is 
Explanation:
From the question we are told that
The speed of the rope with hook is
The angle is 
The speed at which it hits top of the wall is 
Generally from kinematic equation we have that

Here h is the height of the wall so
![[16.3 sin (65)]^2 = [24.1 sin (65)] ^2+ 2 (-9.8)* h](https://tex.z-dn.net/?f=%5B16.3%20sin%20%2865%29%5D%5E2%20%3D%20%20%5B24.1%20sin%20%2865%29%5D%20%5E2%2B%20%20%202%20%28-9.8%29%2A%20h)
=> 
Weight = (mass) x (gravity)
On Earth ...
Weight = (1 kg) x (9.8 m/s^2)
Weight = 9.8 Newtons