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Pavlova-9 [17]
3 years ago
7

A positive and a negative charge, each with a magnitude of 1.41 x 10^-5 C, are separated by a distance of 0.44 m. Find the force

on each of the particles.
Physics
1 answer:
vredina [299]3 years ago
6 0
For this question, we use the Coulumb's law to calculate the force on each particles. In this law, force between point charges are said to be proportional to product of each charge and is  indirectly proportional to the distance of both charges. We do as follows:

F= kq(1)q(2)/d^2 
  = (9x10^9).(1.41 x 10^-5 C).(-<span>1.41 x 10^-5 C</span><span>)/.44^2 
</span>  = 4.067 N


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What is the eulerian description of fluid motion how does it differ from the lagrangian description?
Alex_Xolod [135]

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3 0
2 years ago
A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.
fomenos

Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

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The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

Gravitational force on an object = mg

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8 0
3 years ago
Read 2 more answers
The power in an electric circuit varies inversely with the resistance. If the power is 2,200 watts when the resistance is 25 ohm
valentinak56 [21]

Answer:

The value of resistance when power is 1100 watts = R_{2} = 50 ohms

Explanation:

Power P_{1} = 2200 Watts

Resistance R_{1} = 25 ohms

Power P_{2} = 1100 Watts

Resistance R_{2} = we have to calculate

Given that the power in an electric circuit varies inversely with the resistance

⇒ P ∝ \frac{1}{R}

⇒ \frac{P_{2} }{P_{1} } = \frac{R_{1} }{R_{2} }

⇒ \frac{1100}{2200} = \frac{25}{R_{2} }

⇒ R_{2} = 50 ohms

This is the value of resistance when power is 1100 watts.

6 0
3 years ago
How do I convert 14.8 cm into MEters?
stellarik [79]
Multiply it by a fraction equal to ' 1 ', like this:

(14.8 cm) x (1 meter/100 cm) = 14.8/100 = 0.148 meter
6 0
3 years ago
Read 2 more answers
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