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3 years ago

What is the definition of recoil velocity?

2 answers:

6 0

Recoil is the speed with which the rifle or pistols recoils when the bullet is fired if the gun bullet and the fun mount were frictionless the equation bullet mass times bullet acceleration equals gun mass times gun recoil acceleration

Zinaida [17]3 years ago

3 0

"Recoil velocity is the speed with which the rifle or pistol recoils when the bullet is fired ".
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A wooden block with mass 1.05 kg is placed against a compressed spring at the bottom of a slope inclined at an angle of 35.0 deg

Svet_ta [14]

Answer:

Explanation:

energy stored in spring initially

= kinetic + potential energy of block + energy dissipated by friction

= 1/2 mv² + mgh + μ mgcosθ x d

m is mass , v is velocity at top position , h is vertical height , μ is coefficient of friction ,θ is angle of inclination of plane

= m (1/2 v² + gh + μ gcosθ x d )

= 1.05 ( .5 x 5.1² + 9.8 x 4.9 sin35 + .55 x 9.8 cos35 x 4.9 )

= 1.05 ( 13.005 + 27.543 + 21.635)

= 65.3 J .

4 0

2 years ago

2. Can you rearrange the equation F = kx to get k on one side of the equation

Bumek [7]

k = f/x

x = f/k

( / means divide )

5 0

3 years ago

A mass weighing 4 lb stretches a spring 2 in. Suppose that the mass is given an additional 6-in displacement in the positive dir

givi [52]

Answer:

$\frac{1}{8} y'' + 2y' + 24y=0$

Explanation:

The standard form of the 2nd order differential equation governing the motion of mass-spring system is given by

$my'' + \zeta y' + ky=0$

Where m is the mass, ζ is the damping constant, and k is the spring constant.

The spring constant k can be found by

$w - kL=0$

$mg - kL=0$

$4 - k\frac{1}{6}=0$

$k = 4\times 6 =24$

The damping constant can be found by

$F = -\zeta y'$

$6 = 3\zeta$

$\zeta = \frac{6}{3} = 2$

Finally, the mass m can be found by

$w = 4$

$mg=4$

$m = \frac{4}{g}$

Where g is approximately 32 ft/s²

$m = \frac{4}{32} = \frac{1}{8}$

Therefore, the required differential equation is

$my'' + \zeta y' + ky=0$

$\frac{1}{8} y'' + 2y' + 24y=0$

The initial position is

$y(0) = \frac{1}{2}$

The initial velocity is

$y'(0) = 0$

6 0

2 years ago

When an object is lifted against the force of gravity it has gravitational potential energy. The energy depends on the object's

USPshnik [31]

The answer is actually True, I just took the test and it was correct.

5 0

3 years ago

Read 2 more answers

Sohan said to Geeta I have done my work change the following sentence into indirect

12345 [234]

Answer:

Sohan told Geeta that i had done my work

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3 years ago