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Ad libitum [116K]
3 years ago
12

How many hydrogen atoms are in 8.80 mol of ammonium sulfide

Chemistry
1 answer:
vladimir1956 [14]3 years ago
6 0
Assuming that the ammonium sulfide formula is (NH4)2S then you can see that there are 2 nitrogen, 8 hydrogen and 2 sulfur atoms for every ammonium sulfide. If the amount of ammonium sulfide is 8.9 moles, then the number of hydrogen atoms should be: 8/1 * 8.9 mol= 71.2 moles
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How does the smell of food being cooked spread so fast ???
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Answer:

When we cook food in the kitchen, that's the region of higher concentration of the smell. By diffusion, the smell spreads to the whole room and thereby whole house, so anyone standing at a distance, can smell it.

5 0
3 years ago
Read 2 more answers
Many enzymes are inhibited irreversibly by heavy metal ions such as Hg2+ , Cu2+ , or Ag+ , which can react with essential sulfhy
3241004551 [841]

Answer:

The minimum molecular weight of the enzyme is 29.82 g/mol

Explanation:

<u>Step 1:</u> Given data

The volume of the solution = 10 ml = 10*10^-3L

Molarity of the solution = 1.3 mg/ml

moles of AgNO3 added = 0.436 µmol = 0.436 * 10^-3 mmol

<u>Step 2:</u> Calculate the mass

Density = mass/ volume

1.3mg/mL = mass/ 10.0 mL

mass = 1.3mg/mL *10.0 mL = 13mg

<u>Step 3:</u> Calculate minimum molecular weight

Molecular weight = mass of the enzyme / number of moles

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Molecular weight = 29.82 g/mole

The minimum molecular weight of the enzyme is 29.82 g/mol

7 0
3 years ago
If 0.500 mol of NaN3 react what mass I'm grams of nitrogen would result
klemol [59]
Looks like 3*.5 mol of N, or 1.5*.5 N2 
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6 0
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In the alveoli and lung capillaries, co2 and o2 are exchanged by means of _____.
-Dominant- [34]
Through hemoglobin transport in blood, material exchange is carried out on the alveolar membrane.
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3 years ago
15g of FeCI3 is dissolved in 450 mL of solution. What is the concentration of [CI-]?
storchak [24]

The concentration of [CI-] : 0.617 M

<h3>Further explanation</h3>

FeCl₃ dissolved in 450 mL of solution(will dissociate )

Reaction

FeCl₃⇒Fe³⁺+3Cl⁻

  • mol FeCl₃(MW=162,2 g/mol)

\tt \dfrac{15}{162.2}=0.0925

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\tt \dfrac{3}{1}\times 0.0925=0.2775

  • molarity of Cl⁻ :

\tt \dfrac{0.2775}{0.45}=0.617~M

7 0
3 years ago
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