What are alternative periodic tables

identify the reagents necessary to achieve each of the following transformations o3 dms, pcc, ch2cl, h2so4,h2o,hgso4

hoa [83]

the reagents necessary to convert alcohol to ketone $Na_2Cr_2O_7 , H_2O$ which involves oxidation of alcohols.

<h3>What is oxidation of alcohols?</h3>

Alcohol oxidation is a significant organic chemistry process. Secondary alcohols can be oxidized to produce ketones, while primary alcohols can be oxidized to produce aldehydes and carboxylic acids.
In contrast, tertiary alcohols cannot be oxidized without the C-C bonds in the molecule being broken.
In order to cause primary alcohols to oxidize into aldehydes

$Cr_2O_7 ^-^2$ (dichromate)
$CrO_3$ /pyridine (Collins reagent)
Chromium pyridinium compound (PCC)
Dichromate of pyridinium (PDC, Cornforth reagent)
Periodinane by Dess-Martin
Oxalyl chloride with dimethylsulfoxide (DMSO) for Swern

oxidation of secondary alcohols to ketones

$Cr_2O_7 ^-^2$ (dichromate)
$CrO_3$ /pyridine (Collins reagent)
Chromium pyridinium compound (PCC)
Dichromate of pyridinium (PDC, Cornforth reagent)
Periodinane by Dess-Martin
Oxalyl chloride and dimethyl sulfoxide (DMSO) (Swern oxidation)
$CrO_3, H_2SO_4$ /acetone (Jones oxidation)
Acetone with aluminum isopropoxide (Oppenauer oxidation)

To learn more about oxidation of alcohols with the given link

brainly.com/question/7207863

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<u>Question:</u>

Identify the reagents necessary to achieve each of the following transformations

$a. O_3 , DMS$

$b.H_2SO_4 , H_2O , HgSO_4$

$c.Na_2Cr_2O_7 , H_2O$

$d.Fe ^ {2+}, NaOH$

3 0

2 years ago

Why is it that you can not feel earths movement but you can observes its effects

ss7ja [257]

The correct answer would be we have no other frame of reference besides the sky. We could actually tell we are moving because of the shifting of stars in the sky over time. But really, “A” would be your answer. We have the same momentum of the earth. It’s like being on a train at a constant speed. The only way you know you’re moving is if you look out the window or the speed changes causing you to be pushed around. Same thing with earth, our only reference is the sky

5 0

3 years ago

An orbital is the space occupied by a pair of electrons.<br> true or false??

Anvisha [2.4K]

Answer:

True

Explanation:

An orbital is is the space occupied by a pair of electrons. The maximum number of electrons in an orbital is 2.

The maximum number of electrons in in the orbitals are two.

For s-sublevel with one orbital we have two electrons

p-sublevel with three orbitals we have six electrons

d - sublevel with five orbitals we have ten electrons

f - sublevel with seven orbitals we have fourteen electrons

Each orbital can take a maximum of two electrons.

7 0

3 years ago

URGENT<br> What is the total volume of a lead can if it has a mass of 800g.

Sonja [21]

Answer:

750

Explanation:

5 0

3 years ago

A standard solution of FeSCN2+ is prepared by combining 9.0 mL of 0.20 M Fe(NO3)3 with 1.0 mL of 0.0020 M KSCN . The standard so

Xelga [282]

Answer : The equilibrium concentration of $SCN^-$ in the trial solution is $4.58\times 10^{-8}M$

Explanation :

First we have to calculate the initial moles of $Fe^{3+}$ and $SCN^-$ .

$\text{Moles of }Fe^{3+}=\text{Concentration of }Fe^{3+}\times \text{Volume of solution}$

$\text{Moles of }Fe^{3+}=0.20M\times 9.0mL=1.8mmol$

and,

$\text{Moles of }SCN^-=\text{Concentration of }SCN^-\times \text{Volume of solution}$

$\text{Moles of }SCN^-=0.0020M\times 1.0mL=0.0020mmol$

The given balanced chemical reaction is,

$Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons FeSCN^{2+}(aq)$

Since 1 mole of $Fe^{3+}$ reacts with 1 mole of $SCN^-$ to give 1 mole of $FeSCN^{2+}$

The limiting reagent is, $SCN^-$

So, the number of moles of $FeSCN^{2+}$ = 0.0020 mmole

Now we have to calculate the concentration of $FeSCN^{2+}$ .

$\text{Concentration of }FeSCN^{2+}=\frac{0.0020mmol}{9.0mL+1.0mL}=0.00020M$

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

where,

A = absorbance of solution

C = concentration of solution

l = path length

$\epsilon$ = molar absorptivity coefficient

$\epsilon$ and l are same for stock solution and dilute solution. So,

$\epsilon l=\frac{A}{C}=\frac{0.480}{0.00020M}=2400M^{-1}$

For trial solution:

The equilibrium concentration of $SCN^-$ is,

$[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]$

$[SCN^-]_{initial}$ = 0.00050 M

Now calculate the $[FeSCN^{2+}]$ .

$C=\frac{A}{\epsilon l}=\frac{0.220}{2400M^{-1}}=9.17\times 10^{-5}M$

Now calculate the concentration of $SCN^-$ .

$[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]$

$[SCN^-]_{eqm}=(0.00050M)-(9.17\times 10^{-5}M)$

$[SCN^-]_{eqm}=4.58\times 10^{-8}M$

Therefore, the equilibrium concentration of $SCN^-$ in the trial solution is $4.58\times 10^{-8}M$

5 0

3 years ago