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kakasveta [241]
3 years ago
11

How many mL of 14.5M lithium carbonate solution must be used to deliver 4.20 g of lithium ion

Chemistry
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

10.3 g Li) / (6.9410 g Li/mol) x (1 mol Li3PO4 / 3 mol Li) / (0.750 mol/L Li3PO4) = 0.6595 L = 660. mL

Explanation:

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The concentration of a biomolecule insdie a rod-shaped prokaryotic cell is 0.0051 M. Calculate the number of molecule inside the
Ann [662]

<u>Answer:</u> The number of molecules inside the cell are 2.2\times 10^6

<u>Explanation:</u>

We are given a prokaryotic cell, which is in the shape of rod or cylinder.

The equation used to calculate the volume of cylinder is:

V=\pi r^2h

where,

V = volume of cell = ?

r = radius of the celle = \frac{d}{2}=\frac{1.7\mu m}{2}=0.85\mu m=8.5\times 10^{-7}m     (Conversion factor: 1m=10^6\mu m )

h = length of the cell = 3.1\mu m=3.1\times 10^{-6}m

Putting values in above equation, we get:

V=(3.14)\times (8.5\times 10^{-7})^2\times 3.1\times 10^{-6}\\\\V=7.033\times 10^{-18}m^3

To calculate the number of moles for given molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of biomolecule = 0.0051 M

Volume of solution =  7.033\times 10^{-18}m^3=7.033\times 10^{-15}L     (Conversion factor:  1m^3=1000L )

Putting values in above equation, we get:

0.0051M=\frac{\text{Moles of biomoleculel}}{7.033\times 10^{-15}L}\\\\\text{Moles of biomolecule}=(0.0051mol/L\times 7.033\times 10^{-15}L)=3.59\times 10^{-17}mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules

So, 3.59\times 10^{-17} moles of a biomolecule will contain = (3.59\times 10^{-17}\times 6.022\times 10^{23}=2.2\times 10^6 number of molecules

Hence, the number of molecules inside the cell are 2.2\times 10^6

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Blood ph is kept near a value of 7.3 - 7.5 because of
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If the pH becomes higher, then the blood will become basic in nature and it can also leas to the death of the person.

That is why the pH of the blood is maintianed at neutral value of 7.0 to 7.5

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