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kakasveta [241]
3 years ago
11

How many mL of 14.5M lithium carbonate solution must be used to deliver 4.20 g of lithium ion

Chemistry
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

10.3 g Li) / (6.9410 g Li/mol) x (1 mol Li3PO4 / 3 mol Li) / (0.750 mol/L Li3PO4) = 0.6595 L = 660. mL

Explanation:

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Calculate %ic of the interatomic bonds for the intermetallic compound al6mn. on the basis of this result, what type of interatom
pashok25 [27]

Answer : % ionic character is 0.20%

              Bonding between the two metals will be purely metallic.

Explanation: For the calculation of % ionic character, we use the formula

\% \text{ ionic character}= [1-e^{\frac{-(X_A-X_B)^2)}{4}}]\times(100\%)

where X_A & X_B are the Pauling's electronegativities.

The table attached has the values of electronegativities, by taking the values of Al and Mn from there,

X_{Al}=1.61

X_{Mn}=1.55

Putting the values in the electronegativity formula, we get

\% \text{ ionic character}= [1-e^{\frac{-(1.61-1.55)^2)}{4}}]\times(100\%)

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Now, there are 3 types of inter atomic bonding

1) Ionic Bonding: It refers to the chemical bond in which there is complete transfer of valence electrons between atoms

2) Covalent Bonding: It refers to the chemical bond involving the sharing of electron pairs between 2 atoms.

3) Metallic Bonding: It refers to the chemical bond in which there is an electrostatic force between the positively charged metal ions and delocalised electrons.

In Al_6Mn compound, the % ionic character is minimal that is \sim0.20% and there are two metal ions present, therefore this compound will have metallic bonding.

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