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3 years ago

Michael Faraday was one of the first scientists to experiment with motors. How did Faraday design his first motor?

2 answers:

5 0

The correct option is D.
Micheal Friday devised a wire which hanged down into a glass vessel that has a bar magnet secured at the bottom. He then filled the glass vessel with Mercury and connected the apparatus to a battery. This sent electricity through the wire, thus creating a magnetic field around it. This field interacted with the field around the magnet and cause the wire to rotate clock wisely.

mamaluj [8]3 years ago

5 0

Answer:

it is d

Explanation:

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What is the smallest part of an element

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An atom is the smallest part of an element

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3 years ago

Read 2 more answers

How fast does a 3 kg rocket accelerate if a force of 140 N is applied?

elixir [45]

<h3>Answer:</h3>

46.67 m/s²

<h3>Explanation:</h3>

<u>We are given;</u>

Mass of a rocket = 3 kg
Force applied = 140 N

we are supposed to calculate the acceleration of the rocket;

We are going to use the second Newton's law of motion;
According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.

Therefore;

F = Ma

In this case;

Rearranging the formula

a = F ÷ m

= 140 N ÷ 3 kg

= 46.67 m/s²

Thus, the acceleration of the rocket is 46.67 m/s²

3 0

4 years ago

The graph below shows the composition of the air we breathe. Which of the following statements correctly classified the air we b

levacccp [35]

Answer:

D. The air we breathe is a homogeneous mixture because it has substances but the same appearance throughout.

Explanation:

The air we breathe is a homogeneous mixture.

Air is a mixture of many gases. A homogeneous mixture is one whose constituents exists in one phase.

Air is a gas - gas mixtures.

A mixture has indefinite composition. They consist of two or more elements and or compounds in any proportion by mass.

Constituents retain their identities i.e. physical properties are retained.

8 0

3 years ago

There are many well-documented cases of people surviving falls from heights greater than 20.0 m. In one such case, a 55.0 kg wom

bixtya [17]

1a) -192.7g

1b) 0.0126 s

2) 1309 kg m/s

3) $1.04\cdot 10^5 N$

Explanation:

1a)

First of all, we have to find the velocity of the womena just before hitting the ground.

Since the total mechanical energy is conserved during the fall, the initial gravitational potential energy of the woman when she is at the top is entirely converted into kinetic energy.

So we can write:

$mgh=\frac{1}{2}mv^2$

where

m = 55.0 kg is the mass of the woman

$g=9.8 m/s^2$ is the acceleration due to gravity

h = 29.0 m is the initial height of the woman

v is her final speed

Solving for v,

$v=\sqrt{2gh}=\sqrt{2(9.8)(29.0)}=23.8 m/s$

Then, when the woman hits the soil, she is decelerated until a final velocity

$v'=0$

So we can find the deceleration using the suvat equation:

$v'^2-v^2=2as$

where

s = 15.0 cm = 0.15 m is the displacement during the deceleration

Solving for a,

$a=\frac{v'^2-v^2}{2s}=\frac{0-23.8^2}{2(0.15)}=-1888.3 m/s^2$

In terms of g,

$a=\frac{-1888.3}{9.8}=-192.7g$

1b)

Here we want to find the time it takes for the woman to stop.

Since her motion is a uniformly accelerated motion, we can do it by using the following suvat equation:

$v'=v+at$

where here we have:

v' = 0 is the final velocity of the woman

v = 23.8 m/s is her initial velocity before the impact

$a=-1888.3 m/s^2$ is the acceleration of the woman

t is the time of the impact

Solving for t, we find:

$t=\frac{v'-v}{a}=\frac{0-23.8}{-1888.3}=0.0126 s$

So, the woman took 0.0126 s to stop.

The impulse exerted on an object is equal to the change in momentum experienced by the object.

Therefore, it is given by:

$I=\Delta p =m(v'-v)$

where

$\Delta p$ is the change in momentum

m is the mass of the object

v is the initial velocity

v' is the final velocity

Here we have:

m = 55.0 kg is the mass of the woman

v = 23.8 m/s is her initial velocity before the impact

v' = 0 is her final velocity

So, the impulse is:

$I=(55.0)(0-23.8)=-1309 kg m/s$

where the negative sign indicates the direction opposite to the motion; so the magnitude is 1309 kg m/s.

The impulse exerted on an object is related to the force applied on the object by the equation

$I=F\Delta t$

where

I is the impulse

F is the average force on the object

$\Delta t$ is the time of the collision

Here we have:

$I=1309 kg m/s$ is the magnitude of the impulse

$\Delta t = 0.0126 s$ is the duration of the collision

Solving for F, we find the magnitude of the average force:

$F=\frac{I}{\Delta t}=\frac{1309}{0.0126}=1.04\cdot 10^5 N$

7 0

4 years ago

Nick parks his car at Target and walks 150 ft. north to get to the store. On his way back to the car, he walks 50 ft. before pau

mr Goodwill [35]

75 steps is what he’s missing

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3 years ago