The electric force between two charges is:
F = (9 x 10⁹) Q₁ Q₂ / D²
F is the force, in Newtons
Q₁ and Q₂ are the two charges, in Coulombs
D is the distance between them, in meters
For these two particles:
F = (9 x 10⁹) (0.35) (0.35) / (1)²
F = (9 x 0.35 x 0.35 x 10⁹) / (1)
<em>F = 1.10 x 10⁹ Newtons</em>
Thatsa lotta force . . . like <em>124 thousand tons</em> !
The reason it's so big is because the charges in this question are so big ... 0.35 Coulombs each. 1 Coulomb is a huge amount of charge.
Each of the particles feels the same force, pushing it away from the other particle. (The electric force between two charges is always the same in both directions, just like the gravitational force between two masses.)
The 7.0-kilogram bowling ball has a momentum of 42kgm/s whike the 0.064-kilogram golf ball has a momentum of 3.84kgm/s
Bowling ball is your answer
Answer:
a) a = 2.35 m/s^2
Explanation:
(a) In order to calculate the magnitude of the acceleration of the ball, you use the following formula, for the position of the ball:
(1)
x: position of the ball after t seconds = 87 m
t: time = 8.6 s
a: acceleration of the ball = ?
vo: initial velocity of the ball = 0 m/s
You solve the equation (1) for a:
You replace the values of the parameters in the previous equation:
The acceleration of the ball is 2.35 m/s^2
In the first figure, the surface absorbs all colors except for green light, which is reflected: so, the surface will appear as green to our eyes, because green is the only color which is reflected by that surface.
Similarly, in the second figure, the surface absorbs all colors except for blue, and so the surface will appear blue to our eyes.
In the third figure, the surface absorbs all colors, so it will appear black to our eyes (because no colors are reflected, and black=absence of colors).
In the fourth figure, all colors are reflected: this means the surface will appear white to our eyes (white= sum of all colors).
Answer:
a) 
b) imagen adjunta
Explanation:
a) Primero debemos hacer la conversión de 81 km/h a m/s, esto es 22.5 m/s.
Ahora, usando la ecuacion cinemática, en un movimiento acelerado tenemos:
Queremos encontrar la posición hasta detenerse, osea vf = 0.
b) Para este caso el gráfico se encuentra adjunto.
Espero que te sirva de ayuda!
