3 years ago

If you used 16 gallons when driving 367 miles, what was your gas mileage over that distance

Physics

1 answer:

White raven [17]3 years ago

6 0

Your gas mileage would be 22.93 miles per gallon.

You might be interested in

NEED HELP!!! ANSWER THESE 4 QUESTIONS FOR 20 POINTS!!!! PLEASE ANSWER!! I WILL GIVE YOU BRAINEST

MatroZZZ [7]

Answer:

1)A

2)C

3)A

4)C

Pls give brainliest

I ACTUALLY NEED IT!!!

5 0

2 years ago

What is a substance?

Anna007 [38]

Answer:

A physical matter

Explanation:

A kind of matter with uniform physical properties

3 0

3 years ago

A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t

enot [183]

Here we will the speed of seagull which is v = 9 m/s

this is the speed of seagull when there is no effect of wind on it

now in part a)

if effect of wind is in opposite direction then it travels 6 km in 20 min

so the average speed is given by the ratio of total distance and total time

$v_{avg} = \frac{6000}{20*60}$

$v_{avg} = 5m/s$

now since effect of wind is in opposite direction then we can say

$V_{net} = v_{bird} - v_{wind}$

$5 = 9 - v_{wind}$

$v_{wind}= 4 m/s$

Part b)

now if bird travels in the same direction of wind then we will have

$v_{net}= v_{bird} + v_{wind}$

$v_{net} = 9 + 4 = 13 m/s$

now we can find the time to go back

$time = \frac{distance}{speed}$

$time = \frac{6000}{13}$

$time = 7.7 minutes$

Part c)

Total time of round trip when wind is present

$T = t_1 + t_2$

$T = 20 + 7.7 = 27.7 min$

now when there is no wind total time is given by

$T = \frac{6000}{9} + \frac{6000}{9}$

$T = 22.22 min$

So due to wind time will be more

4 0

4 years ago

Lance arrives early at the airport (with flowers and balloons in hand) to welcome a friend. Her plane is delayed. While waiting,

Tju [1.3M]

Answer:

Explanation:

Lance was never a bright young fella so he rolled down a hill and lost his left boot

4 0

3 years ago

3.) An engineer is designing the runway for an airport. Of the planes that will use the airport,

scoray [572]

Answer: 704

Explanation:Vi = 0 m/s

vf = 65 m/s

a = 3 m/s2

d = ??

vf2 = vi2 + 2*a*d

(65 m/s)2 = (0 m/s)2 + 2*(3 m/s2)*d

4225 m2/s2 = (0 m/s)2 + (6 m/s2)*d

(4225 m 2/m2)/(6 m/s2) = d

d = 704 m

5 0

3 years ago

Read 2 more answers