Answer:
a) F = 680 N, b) W = 215 .4 J
, c) F = 1278.4 N
Explanation:
a) Hooke's law is
F = k x
To find the displacement (x) let's use the elastic energy equation
= ½ k x²
k = 2
/ x²
k = 2 85.0 / 0.250²
k = 2720 N / m
We replace and look for elastic force
F = 2720 0.250
F = 680 N
b) The definition of work is
W = ΔEm
W =
- ![K_{eo}](https://tex.z-dn.net/?f=K_%7Beo%7D)
W = ½ k (
² - x₀²)
The final distance
= 0.250 +0.220
= 0.4750 m
We calculate the work
W = ½ 2720 (0.47² - 0.25²)
W = 215 .4 J
We calculate the strength
F = k ![x_{f}](https://tex.z-dn.net/?f=x_%7Bf%7D)
F = 2720 0.470
F = 1278.4 N
Gravitational potential energy above a reference level is M G H .
In this story,
-- M = 25kg
-- H = 15m
and if the story takes place on Earth, then
-- G = about 9.8m/s².
PE = (M) (G) (H) = (25) (15) (9.8) = <em>3,675 joules</em> .
That's the gravitational potential energy acquired by the suitcase
in the process of being lifted 15 meters straight up.
Sadly, human physical effort is far from 100% efficient, and the woman in
the story has to expend a lot more energy than that just to lift the suitcase
up the stairs. AND PLUS don't forget that she also has to come up with
enough additional energy to increase the potential energy of <em>her own</em> mass,
no matter how dainty it may be, by 15 vertical meters' worth.
Now 25 kg = about 55 pounds,
and 15 meters = about 50 feet, or something like 4 to 5 stories
You can be sure that some beads of glow highlight her forehead
by the time she's done with this job.
Answer:
C) It increases to 2.0 cm
Explanation:
In a double-slit diffraction experiment, the distance on the screen between two adjacent maxima is given by
![\Delta y = \frac{\lambda D}{d}](https://tex.z-dn.net/?f=%5CDelta%20y%20%3D%20%5Cfrac%7B%5Clambda%20D%7D%7Bd%7D)
where
is the wavelength of the wave
D is the distance of the screen from the slits
d is the separation between the slits
In this problem, the initial distance between adjacent maxima is 1.0 cm. Later, the slit separation is cut in a half, which means that the new slit separation is
![d'=\frac{d}{2}](https://tex.z-dn.net/?f=d%27%3D%5Cfrac%7Bd%7D%7B2%7D)
Substituting into the equation, we find that the new separation between the maxima is
![\Delta y' = \frac{\lambda D}{d/2}=2(\frac{\lambda D}{d})=2\Delta y](https://tex.z-dn.net/?f=%5CDelta%20y%27%20%3D%20%5Cfrac%7B%5Clambda%20D%7D%7Bd%2F2%7D%3D2%28%5Cfrac%7B%5Clambda%20D%7D%7Bd%7D%29%3D2%5CDelta%20y)
So, the distance increases by a factor 2: therefore, the new separation between the maxima will be 2.0 cm.
Answer:
if you rub an negative object against a positive object, the negative electrons will go to the positive electrons making the object that was rubbed positive
Explanation:
The equigravity between two planets is determined from the product and their masses and square of distance between them.
<h3>Gravitational force between two planets</h3>
The gravitational force between two planets is calculated as follows;
F = GM₁M₂/R²
where;
- G is universal gravitation constant
- M₁ is mass of first planet
- M₂ is mass of the second planet
- R is the distance between the two planets
Use the mass ratio of the two planets to determine their individual masses.
Thus, the equigravity between two planets is determined from the product and their masses and square of distance between them.
Learn more about gravitational force here: brainly.com/question/72250
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