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Gemiola [76]
3 years ago
9

Before the cells in a person's body can use the food that the person eats, the food must be A. chemically broken down into sugar

. B. chemically changed into heat. C. physically changed into a solid. D. physically heated to 100°C.
Physics
2 answers:
larisa86 [58]3 years ago
6 0
A chemically broken down into sugar
exis [7]3 years ago
3 0

Answer:

Answer choice A

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If two objects of unequal mass collide, both objects will continue to move in the direction of
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Assuming this is an elastic collision, they go in the direction of the object with more mass
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Consider an object with s=12cm that produces an image with s′=15cm. Note that whenever you are working with a physical object, t
Leni [432]

A. 6.67 cm

The focal length of the lens can be found by using the lens equation:

\frac{1}{f}=\frac{1}{s}+\frac{1}{s'}

where we have

f = focal length

s = 12 cm is the distance of the object from the lens

s' = 15 cm is the distance of the image from the lens

Solving the equation for f, we find

\frac{1}{f}=\frac{1}{12 cm}+\frac{1}{15 cm}=0.15 cm^{-1}\\f=\frac{1}{0.15 cm^{-1}}=6.67 cm

B. Converging

According to sign convention for lenses, we have:

- Converging (convex) lenses have focal length with positive sign

- Diverging (concave) lenses have focal length with negative sign

In this case, the focal length of the lens is positive, so the lens is a converging lens.

C. -1.25

The magnification of the lens is given by

M=-\frac{s'}{s}

where

s' = 15 cm is the distance of the image from the lens

s = 12 cm is the distance of the object from the lens

Substituting into the equation, we find

M=-\frac{15 cm}{12 cm}=-1.25

D. Real and inverted

The magnification equation can be also rewritten as

M=\frac{y'}{y}

where

y' is the size of the image

y is the size of the object

Re-arranging it, we have

y'=My

Since in this case M is negative, it means that y' has opposite sign compared to y: this means that the image is inverted.

Also, the sign of s' tells us if the image is real of virtual. In fact:

- s' is positive: image is real

- s' is negative: image is virtual

In this case, s' is positive, so the image is real.

E. Virtual

In this case, the magnification is 5/9, so we have

M=\frac{5}{9}=-\frac{s'}{s}

which can be rewritten as

s'=-M s = -\frac{5}{9}s

which means that s' has opposite sign than s: therefore, the image is virtual.

F. 12.0 cm

From the magnification equation, we can write

s'=-Ms

and then we can substitute it into the lens equation:

\frac{1}{f}=\frac{1}{s}+\frac{1}{s'}\\\frac{1}{f}=\frac{1}{s}+\frac{1}{-Ms}

and we can solve for s:

\frac{1}{f}=\frac{M-1}{Ms}\\f=\frac{Ms}{M-1}\\s=\frac{f(M-1)}{M}=\frac{(-15 cm)(\frac{5}{9}-1}{\frac{5}{9}}=12.0 cm

G. -6.67 cm

Now the image distance can be directly found by using again the magnification equation:

s'=-Ms=-\frac{5}{9}(12.0 cm)=-6.67 cm

And the sign of s' (negative) also tells us that the image is virtual.

H. -24.0 cm

In this case, the image is twice as tall as the object, so the magnification is

M = 2

and the distance of the image from the lens is

s' = -24 cm

The problem is asking us for the image distance: however, this is already given by the problem,

s' = -24 cm

so, this is the answer. And the fact that its sign is negative tells us that the image is virtual.

3 0
3 years ago
Please need help with this
PtichkaEL [24]
Through is the answer to your question
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A string fixed at both ends is 8.40 m long and has a mass of 0.120 kg. It is subjected to a tension of 96.0 N and set oscillatin
Luden [163]

Answer:

81.9756 m/s

16.8 m

4.8795 Hz

Explanation:

m = Mass of string = 0.12 kg

L = Length of string = 8.4 m

T = Tension on string = 96 N

Linear density is given by

\mu=\dfrac{m}{L}\\\Rightarrow \mu=\dfrac{0.12}{8.4}

Spee of the wave is given by

v=\sqrt{\dfrac{T}{\mu}}\\\Rightarrow v=\sqrt{\dfrac{96}{\dfrac{0.12}{8.4}}}\\\Rightarrow v=81.9756\ m/s

The speed of the waves on the string is 81.9756 m/s

Wavelength is given by

\lambda=2L\\\Rightarrow \lambda=2\times 8.4\\\Rightarrow \lambda=16.8\ m

The longest possible wavelength is 16.8 m

Frequency is given by

f=\dfrac{v}{\lambda}\\\Rightarrow f=\dfrac{81.9756}{16.8}\\\Rightarrow f=4.8795\ Hz

The frequency of the wave is 4.8795 Hz

3 0
3 years ago
you see an insect egg lying on a leaf. What is the next step? Name or describe the stage you would expect to see come out from t
Marianna [84]

Answer:

Metamorphosis are the series of processes involved in the development of organisms, mostly insects after the egg is hatched.

Insects undergo complete or incomplete metamorphosis

Complete metamorphosis involves 4 stages which is the development from egg to larva to pups to adults in a step wise manner e.g butterfly, moth etc

Egg—> Larva—> Pupa—> Adults

In incomplete metamorphosis the stages are 3 and it involves development from egg to nymph to adults. E.g cockroach

Egg—> Nymph—> Adults

4 0
3 years ago
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