Ask question

Ask question

All categories

Nadusha1986 [10]

3 years ago

6

Marissa blows up balloons for a party. She decides how big or small to make each balloon. Why does the air she blows into each b

alloon take up all the space inside the balloon

1 answer:

Oxana [17]3 years ago

5 0

Air is it gas so it fills its container, the balloon, completely.

You might be interested in

What is the mass of 1.5 moles of CO2?

Arisa [49]

1 mole of CO2 has 44g
so 1,5 moles would have 1,5*44=66g
the answer is 1) 66g

8 0

3 years ago

Hii pls help me to balance the equation thanksss

tiny-mole [99]

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

$\boxed{\pmb{\color{gold}{\sf{2SO_{2}(g) + O_{2}(g)\dashrightarrow 2SO_{3}(g)}}}}$

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

7 0

3 years ago

Read 2 more answers

What is love and why it's to forget about it.

kozerog [31]

Answer:

Love is an emotion you feel for someone or something very closely and enjoy spending time with them. Love can be a good thing and bad. It can be bad by being rejected by the person you like or even love. After that you might say you never want love again. But without love you might not be the person you are now. You now might know your mistakes and will do better the next time. Without love you won't have any cherishful moments. You might even turn depressed. But the past is the past, and you must look forward.

7 0

3 years ago

The structural level of a protein least affected by a disruption in hydrogen bonding is the

sergeinik [125]

I think the correct answer from the choices listed above is option A. The structural level of a protein least affected by a disruption in hydrogen bonding is the primary level. The other levels are very much affected by hydrogen bonding. Hope this answers the question.

7 0

4 years ago

Phenolphthalein has a pKa of 9.7 and is colorless in its acid form and pink in its basic form. calculate [In-}/{HIn} for the fol

zvonat [6]

Answer:

1.58x10⁻⁵

2.51x10⁻⁸

0.0126

63.10

Explanation:

Phenolphthalein acts like a weak acid, so in aqueous solution, it has an acid form HIn, and the conjugate base In-, and the pH of it can be calculated by the Handerson-Halsebach equation:

pH = pKa + log[In-]/[HIn]

pKa = -logKa, and Ka is the equilibrium constant of the dissociation of the acid. [X] is the concentrantion of X. Thus,

i) pH = 4.9

4.9 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = - 4.8

[In-]/[HIn] = $10^{-4.8}$

[In-]/[HIn] = 1.58x10⁻⁵

ii) pH = 2.1

2.1 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = -7.6

[In-]/[HIn] = $10^{-7.6}$

[In-]/[HIn] = 2.51x10⁻⁸

iii) pH = 7.8

7.8 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = -1.9

[In-]/[HIn] = $10^{-1.9}$

[In-]/[HIn] = 0.0126

iv) pH = 11.5

11.5 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = 1.8

[In-]/[HIn] = $10^{1.8}$

[In-]/[HIn] = 63.10

6 0

3 years ago