Answer:
Coefficients
Explanation:
Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).
To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.
For example, in this skeleton equation:
H₂ + Cl₂ => HCl
Reactants: Products:
2 hydrogen 1 hydrogen
2 chlorine 1 chlorine
Write the coefficient 2 in the products.
H₂ + Cl₂ => 2HCl
Now both reactant and product sides have 2 chlorine and 2 hydrogen, so the equation is balanced.
Answer:
no
Explanation:
Radium is silvery, lustrous, soft, intensely radioactive. It readily oxidizes on exposure to air, turning from almost pure white to black. Radium is luminescent, corrodes in water to form radium hydroxide. Although is the heaviest member of the alkaline-earth group it is the most volatile.
Answer:

Explanation:
We are given the formula:

This is a molecular formula, because it contains nonmetals.
1. Name the first element
The first element is phosphorous (P). Since this is the first element and there is only one, we don't need a prefix.
2. Second element
The second element is chlorine (Cl). It has a subscript of 5, so we must add the prefix of <u>hepta</u>-.
- Phosphorous heptachlorine
Add the ending of -ide.
- Phosphorous heptachloride
The prefix used for the second element is hepta. The compound name is phosphorous heptachloride.
Answer:
a) Unsaturated
b) Supersaturated
c) Unsaturated
Explanation:
A saturated solution contains the <u>maximum amount of a solute that will dissolve in a given solvent at a specific temperature</u>.
An unsaturated solution contains <u>less solute than it has the capacity to dissolve. </u>
A supersaturated solution, <u>contains more solute than is present in a saturated solution</u>. Supersaturated solutions are not very stable. In time, some of the solute will come out of a supersaturated solution as crystals.
According to these definitions and considering that the solubility of KCl in 100 mL of H₂O at <u>20 °C is 34 g</u>, and at <u>50 °C is 43 g</u> we can label the solutions:
a) 30 g in 100 mL of H₂O at 20 °C ⇒ unsaturated
b) 65 g in 100 mL of H₂O at 50 °C ⇒ supersaturated
c) 42 g in 100 mL of H₂O at 50 °C and slowly cooling to 20 °C to give a clear solution <u>with no precipitate</u> ⇒ unsaturated (if it were saturated it would have had precipitate)
I don’t understand the question sorry