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2 years ago

10

These pairs of forces are known as ____________-reaction pairs because one pushes against the other with an equal but opposite f

orce.

1 answer:

victus00 [196]2 years ago

5 0

Action-reaction pairs

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a coin is dropped from the top of a tall building. determine the coin's (a) velocity and (b) displacement after 1.5 sec.

Lilit [14]

1) v = gt = 10*1.5 = 15 m/s
2) r = gt^2 /2 = 10*(1.5)^2 / 2 = 11.25 meters

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2 years ago

A T-Bar is similar to a_______

dezoksy [38]

Answer:

Donkey

Explanation:

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2 years ago

There is a naturally occurring vertical electric field near the Earth’s surface that points toward the ground. In fair weather c

trasher [3.6K]

Answer:

$\frac{F}{W} = 9.37 \times 10^{-4}$

Explanation:

Radius of the pollen is given as

$r = 12.0 \mu m$

Volume of the pollen is given as

$V = \frac{4}{3}\pi r^3$

$V = \frac{4}{3}\pi (12\mu m)^3$

$V = 7.24 \times 10^{-15} m^3$

mass of the pollen is given as

$m = \rho V$

$m = 7.24 \times 10^{-12}$

so weight of the pollen is given as

$W = mg$

$W = (7.24 \times 10^{-12})(9.81)$

$W = 7.1 \times 10^{-11}$

Now electric force on the pollen is given

$F = qE$

$F = (-0.700\times 10^{-15})(95)$

$F = 6.65 \times 10^{-14} N$

now ratio of electric force and weight is given as

$\frac{F}{W} = \frac{6.65 \times 10^{-14}}{7.1 \times 10^{-11}}$

$\frac{F}{W} = 9.37 \times 10^{-4}$

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2 years ago

A swimmer swims north at 0.10 m/s relative to still water across a river that flows at 0.25 m/s from east to west. Calculate the

ValentinkaMS [17]

0.15 m/s East
If you follow the equation a=vf-vi/t, you'll discover that subtracting the final velocity, 0.25 m/s, by the initial velocity, 0.10 m/s, and divide by zero, (bc there was no given time) the answer is 0.15 m/s East

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2 years ago

An external computer flash drive can hold I gigabyte of data.How many bytes is this

julsineya [31]

A lot. A lot of bytes.

But I suppose you're looking for a more specific answer, huh?

<span>1 Gigabyte = 1,073,741,824 Bytes
</span>
That external computer flash drive can hold 1,073,741,824 bytes of data.

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2 years ago