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3 years ago

10

These pairs of forces are known as ____________-reaction pairs because one pushes against the other with an equal but opposite f

orce.

1 answer:

victus00 [196]3 years ago

5 0

Action-reaction pairs

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86 Km/h convertir a (m/min)

gogolik [260]

Answer: 1433.3 m/min

Explanation:

For 86 Km/h converted to a (m/min), convert kilometers to meters, and hour to minutes

So, 86 Km/h means 86 kilometers per 1 hour

- If 1 kilometer = 1000 metres

86 kilometers = 86 x 1000 = 86,000m

- If 1 hour = 60 minute

1 hour = 60 minutes

In m/min: (86,000m / 60 minute)

= 1433.3 m/min

Thus, 86 Km/h convert to 1433.3 m/min

5 0

3 years ago

HELP PLEASE<br><br> Fill in the blank:<br> The ? of water is 1 g/cm3.

ololo11 [35]

I think it’s density

3 0

3 years ago

Two identical loudspeakers 2.30 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi

Dimas [21]

Answer:

Abby is standing (4.5^2 + 2.3^2)^1/2 from the far speaker

D2 = 5.05 m from the far speaker

The difference in distances from the speakers is

5.05 - 4.5 = .55 m (Let y be wavelength, lambda)

n y = 4.5

(n + 1) y = 5.05 for the speakers to be in phase at smallest wavelength

y = .55 m subtracting equations

f = v / y = 340 / .55 = 618 / sec should be the smallest frequency

8 0

3 years ago

(a) What is the ionization energy of a hydrogen atom that is in the n = 6 excited state? (b) For a hydrogen atom, determine the

crimeas [40]

Answer:

(a) 0.3778 eV

(b) Ratio = 0.0278

Explanation:

The Bohr's formula for the calculation of the energy of the electron in nth orbit is:

$E=\frac {-13.6}{n^2}\ eV$

(a) The energy of the electron in n= 6 excited state is:

$E=\frac {-13.6}{6^2}\ eV$

$E=-0.3778\ eV$

Ionisation energy is the amount of this energy required to remove the electron. Thus, |E| = 0.3778 eV

(b) For first orbit energy is:

$E=\frac {-13.6}{1^2}\ eV$

$E=-13.6\ eV$

$Ratio=\frac {E_6}{E_1}$

$Ratio=\frac {-0.3778}{-13.6}$

Ratio = 0.0278

7 0

3 years ago

A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)

Illusion [34]

The work done against gravity is 100 J

Explanation:

The work done against gravity in order to lift an object is equal to the change in gravitational potential energy of the object:

$W=mg\Delta h$

where

m is the mass of the object

g is the acceleration of gravity

$\Delta h$ is the change in height of the object

For the object in this problem, we have:

m = 5 kg

$g=10 m/s^2$

$\Delta h = 2 m$

Substituting into the equation,

$W=(5)(10)(2)=100 J$

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0

3 years ago