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valentina_108 [34]
2 years ago
11

While driving on a rural road, your right wheels run off the pavement. You should hold the steering wheel firmly and

Physics
1 answer:
Vsevolod [243]2 years ago
3 0

Answer:

The answer is C. Steer in a straight line while gently slowing down

Explanation:

The following are advised when your cars go off the pavement while driving;

firstly, Do not panic.

ensure you hold on to your steering wheel tightly.

keep Steering straight ahead.

ensure you Stay on the shoulder.

Ease up on the accelerator and brake gently.

When you  know you can safely do so, turn back on the road at a much lower speed.

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50 g of liquid Y at 10 Celcius and 200 g of liquid Y at 40Celcius are mixed. Final temperature of the mixture is measured as 15
Sholpan [36]
50 g of liquid X at 10 Celcius and 200 g of liquid Y

mx*cx*(t-tx)+my*cy*(t-ty)=0
cx/cy = - my*(t-ty) : mx*(t-tx) = (my/mx)  * (ty - t) / (t-tx)
cx/cy  = 200/50*(40-15)/(15-10) = 20
cx/cy   = 20



5 0
3 years ago
HELP ME ASAP PLS, ( zoom in on the picture )
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Answer:

the direction of the velocity is downward and the acceleration decreases throughout the motion

Explanation:

since the gradient is negative it is decelerating

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2 years ago
What part of the hammer acts as the fulcrum when the hammer is used to remove a nail
Natali5045456 [20]
The end of it with the dent
6 0
3 years ago
A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change. A) True B) False
bixtya [17]

Answer:

False

Explanation:

Faraday's law gives the relationship between the induced emf and the rate of change of magnetic flux i.e.

\epsilon=\dfrac{-d\phi}{dt}

The given statement "A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change" is false. The reason is that if the rate of change of magnetic flux is greater, then its will induce more emf. It would mean it does not say about emf.

Hence, it is false.

3 0
3 years ago
video for A door 1 m wide, of mass 15 kg, is hinged at one side so that it can rotate without friction about a vertical axis. It
natka813 [3]

Answer:

\omega_f = 0.4\ rad/s

Explanation:

given,

width of door dimension  = 1 m

mass of door = 15 Kg

mass of bullet = 10 g = 0.001 Kg

speed of bullet = 400 m/s

I_{total} =I_{door} + I_{bullet}

I_{total} =\dfrac{1}{3}MW^2 + m(\dfrac{W}{2})^2

a) from conservation of angular momentum  

L_i = L_f  

mv\dfrac{W}{2} = I_{total}\omega_f  

mv\dfrac{W}{2}= (\dfrac{1}{3}MW^2 + m(\dfrac{W}{2})^2)\omega_f

\omega_f= \dfrac{mv\dfrac{W}{2}}{\dfrac{1}{3}MW^2 + m(\dfrac{W}{2})^2}

\omega_f= \dfrac{\dfrac{mv}{2}}{\dfrac{MW }{3}+(\dfrac{mW}{4})}

\omega_f= \dfrac{\dfrac{0.01\times 400}{2}}{\dfrac{15\times 1 }{3}+(\dfrac{0.01\times 1}{4})}

\omega_f = 0.4\ rad/s

8 0
3 years ago
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