Answer:
(a) 0.2618 J
(b) 0.1558 J
(c) 0 J
Explanation:
from Hook's Law,
The energy stored in a stretched spring = 1/2ke²
Ep = 1/2ke² ......................... Equation 1
Where k = spring constant, e = extension, E p = potential energy stored in the spring.
(a) When The spring is stretched to 4.11 cm,
Given: k = 310 N/m, e = 4.11 cm = 0.0411 m
Substituting these values into equation 1
Ep = 1/2(310)(0.0411)²
Ep = 155(0.0016892)
Ep =155×0.0016892
Ep = 0.2618 J.
(b) When the spring is stretched 3.17 cm
e = 3.17 cm = 0.0317 m.
Ep = 1/2(310)(0.0317)²
Ep = 155(0.0317)²
Ep = 155(0.0010049)
Ep = 0.155758 J
Ep ≈ 0.1558 J.
(c) When the spring is unstretched,
e = 0 m, k = 310 N/m
Ep = 1/2(310)(0)²
Ep = 0 J.
The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg
<h3>Data obtained from the question</h3>
- Year 1800 percent = 0.028%
- Year 2013 percent = 0.040%
- Mass of air = 500 Kg
- Difference =?
<h3>How to determine the mass of CO₂ in 500 Kg in year 1800</h3>
- Year 1800 percent = 0.028%
- Mass of air = 500 Kg
- Mass of CO₂ =?
Mass = percent × mass of air
Mass of CO₂ = 0.028% × 500
Mass of CO₂ = 0.14 Kg
<h3>How to determine the mass of CO₂ in 500 Kg in year 2013</h3>
- Year 1800 percent = 0.040%
- Mass of air = 500 Kg
- Mass of CO₂ =?
Mass = percent × mass of air
Mass of CO₂ = 0.040% × 500
Mass of CO₂ = 0.2 Kg
<h3>How to determine the difference</h3>
- Mass of CO₂ in year 1800 = 0.14 Kg
- Mass of CO₂ in year 2013 = 0.2 Kg
- Difference =?
Difference = mass in 2013 - mass in 1800
Difference = 0.2 - 0.14
Difference = 0.06 Kg
Learn more about composition:
brainly.com/question/11617445
#SPJ1
Answer:
(a) Total area is 14.5 roods
(b) Total area is 14674.522 square meters
Explanation:
Area occupied by land = 3 acres
1 acre = 40 perches by 4 perches = 160 square perches
3 acres = 3×160 = 480 square perches
Area occupied by livestock = 25 perches by 4 perches = 100 square perches
Total area = 480 + 100 = 580 square perches
1 rood = 4 perches by 1 perch = 4 square perches
580 square perches = 580/4 = 14.5 roods
(b) Total area = 580 square perches
1 perch = 16.5ft = 16.5/3.2808 = 5.03 meters
580 square perches × (5.03 meters/1 perch)^2 = 580 ×25.3009 square meters = 14674.522 square meters
Answer:
1.0 x 10-14.
Explanation:
We then replace the term on the right side of this equation with a constant known as the water dissociation equilibrium constant, Kw. In pure water, at 25C, the [H3O+] and [OH-] ion concentrations are 1.0 x 10-7 M. The value of Kw at 25C is therefore