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Dominik [7]
3 years ago
7

Any two waves that meet as they travel through the same medium will interact. If the two waves are in phase their crests will co

incide and they will experience _____ interference, producing a wave with a(n) _____ amplitude.
Physics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

constructive

alpitude

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A spring has a force constant of 310.0 N/m. (a) Determine the potential energy stored in the spring when the spring is stretched
skad [1K]

Answer:

(a) 0.2618 J

(b)  0.1558 J

(c) 0 J

Explanation:

from Hook's Law,

The energy stored in a stretched spring = 1/2ke²

Ep = 1/2ke² ......................... Equation 1

Where k = spring constant, e = extension, E p = potential energy stored in the spring.

(a) When The spring is stretched to 4.11 cm,

Given: k = 310 N/m, e = 4.11 cm = 0.0411 m

Substituting these values into equation 1

Ep = 1/2(310)(0.0411)²

Ep = 155(0.0016892)

Ep =155×0.0016892

Ep = 0.2618 J.

(b) When the spring is stretched 3.17 cm

e = 3.17 cm = 0.0317 m.

Ep = 1/2(310)(0.0317)²

Ep = 155(0.0317)²

Ep = 155(0.0010049)

Ep = 0.155758 J

Ep ≈ 0.1558 J.

(c) When the spring is unstretched,

e = 0 m, k = 310 N/m

Ep = 1/2(310)(0)²

Ep = 0 J.

6 0
3 years ago
XXXTENTACION was embarrassed when his stomach A rustled B grumbled C squeaked D chattered What complete the sententence. BTW Rip
Liula [17]

Answer:

b?

Explanation:

5 0
3 years ago
Read 2 more answers
The table shows the percentage of carbon dioxide in the Earth’s atmosphere in the years 1800 and 2013. Calculate the difference
Natalka [10]

The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg

<h3>Data obtained from the question</h3>
  • Year 1800 percent = 0.028%
  • Year 2013 percent = 0.040%
  • Mass of air = 500 Kg
  • Difference =?

<h3>How to determine the mass of CO₂ in 500 Kg in year 1800</h3>
  • Year 1800 percent = 0.028%
  • Mass of air = 500 Kg
  • Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.028% × 500

Mass of CO₂ = 0.14 Kg

<h3>How to determine the mass of CO₂ in 500 Kg in year 2013</h3>
  • Year 1800 percent = 0.040%
  • Mass of air = 500 Kg
  • Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.040% × 500

Mass of CO₂ = 0.2 Kg

<h3>How to determine the difference</h3>
  • Mass of CO₂ in year 1800 = 0.14 Kg
  • Mass of CO₂ in year 2013 = 0.2 Kg
  • Difference =?

Difference = mass in 2013 - mass in 1800

Difference = 0.2 - 0.14

Difference = 0.06 Kg

Learn more about composition:

brainly.com/question/11617445

#SPJ1

7 0
2 years ago
An old manuscript reveals that a landowner in the time of King Arthur held 3.00 acres of plowed land plus a livestock area of 25
iragen [17]

Answer:

(a) Total area is 14.5 roods

(b) Total area is 14674.522 square meters

Explanation:

Area occupied by land = 3 acres

1 acre = 40 perches by 4 perches = 160 square perches

3 acres = 3×160 = 480 square perches

Area occupied by livestock = 25 perches by 4 perches = 100 square perches

Total area = 480 + 100 = 580 square perches

1 rood = 4 perches by 1 perch = 4 square perches

580 square perches = 580/4 = 14.5 roods

(b) Total area = 580 square perches

1 perch = 16.5ft = 16.5/3.2808 = 5.03 meters

580 square perches × (5.03 meters/1 perch)^2 = 580 ×25.3009 square meters = 14674.522 square meters

8 0
3 years ago
What is the equilibrium constant of pure water at 25C
Tcecarenko [31]

Answer:

1.0 x 10-14.

Explanation:

We then replace the term on the right side of this equation with a constant known as the water dissociation equilibrium constant, Kw. In pure water, at 25C, the [H3O+] and [OH-] ion concentrations are 1.0 x 10-7 M. The value of Kw at 25C is therefore

6 0
3 years ago
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