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maxonik [38]
3 years ago
8

What is the definition of the change in free energy? AG=AH + TAS • AG=AH - TAS O AG = AHAS-T AG = AHAS + 1

Chemistry
1 answer:
svetoff [14.1K]3 years ago
4 0

Answer:

\Delta G=\Delta H-T\times \Delta S

Explanation:

The Gibbs free energy in thermodynamics is a potential which is used to calculate maximum of the reversible work which is performed by a specific thermodynamic system at constant temperature (isothermal) as well as pressure (isobaric).

The expression for the change in free energy is:

\Delta G=\Delta H-T\times \Delta S

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5 0
3 years ago
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for a theoretical yield of 22 g and actual yield of 13 g, calculate the percent yield for a chemical reaction
sammy [17]

Answer:

59.09%

Explanation:

13/22*100=59.09%

8 0
3 years ago
Atomic mass number of first 30 elements
dangina [55]

Answer:

Element Atomic Number Atomic Mass

Nickel          27                          58.6934

Cobalt             28                   58.9332

Copper            29                  63.546

Zinc                   30                            65.39

Explanation:

4 0
3 years ago
Balance the following redox reaction occurring in an acidic solution. The coefficient of Mn2+(aq) is given. Enter the coefficien
Vadim26 [7]

Answer:

_5_ AsO2−(aq) + 3 Mn2+(aq) + _2_ H2O(l) → _5_ As(s) + _3_ MnO4−(aq) + _4_ H+(aq)

Explanation:

Step 1:

The unbalanced equation:

AsO2−(aq) + 3 Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

Step 2:

Balancing the equation.

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

The above equation can be balanced as follow:

There are 3 atoms of Mn on the left side of the equation and 1 atom on the right side. It can be balance by putting 3 in front of MnO4− as shown below:

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 12 atoms of O on the right side and a total of 3 atoms on the left side. It can be balance by putting 5 in front of AsO2− and 2 in front of H2O as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 4 atoms of H on the left side and 1 atom on the right side. It can be balance by putting 4 in front of H+ as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + 4H+(aq)

There are 5 atoms of As on the left side and 1 atom on the right side. It can be balance by putting 5 in front of As as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → 5As(s) + 3MnO4−(aq) + 4H+(aq)

Now the equation is balanced

7 0
3 years ago
Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:
jok3333 [9.3K]

Answer:

a) Mo the electron configuration: 42Mo: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d4

Mo3+ - is Paramagnetic

b) Au - [Xe] 4f14 5d10 6s1

For Au+ is not paramagnetic

c) Mn - [Ar] 3d5 4s2

Mn2+ is paramagnetic

d)Hf -[Xe] 4f¹⁴ 5d² 6s²

Hf2+ is not paramagnetic

Explanation:

An atom becomes positively charged when it looses an electron.

Diamagnetism in atom occurs whenever two electrons in an orbital paired equalises with a total spin of 0.

Paramagnetism in atom occurs whenever at least one orbital of an atom has a net spin of electron. That is a paramagnetic electron is just an unpaired electron in the atom.

Here is a twist even if an atom have ten diamagnetic electrons, the presence of at least one paramagnetic electron, makes it to be considered as a paramagnetic atom.

Simply put paramagnetic elements are one that have unpaired electrons, whereas diamagnetic elements do have paired electron.

3 0
3 years ago
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