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2 years ago

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What is the definition of the change in free energy? AG=AH + TAS • AG=AH - TAS O AG = AHAS-T AG = AHAS + 1

1 answer:

svetoff [14.1K]2 years ago

4 0

Answer:

$\Delta G=\Delta H-T\times \Delta S$

Explanation:

The Gibbs free energy in thermodynamics is a potential which is used to calculate maximum of the reversible work which is performed by a specific thermodynamic system at constant temperature (isothermal) as well as pressure (isobaric).

The expression for the change in free energy is:

$\Delta G=\Delta H-T\times \Delta S$

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Which formula represents a hydrocarbon with a double covalent bond?

Nataliya [291]

Answer:

c is the answer

step by step explanation is not

4 0

2 years ago

A sheet of gold weighing 8.8 g and at a temperature of 10.5°C is placed flat on a sheet of iron weighing 19.5 g and at a tempera

timofeeve [1]

Answer:

$T = 36.393\,^{\textdegree}C$

Explanation:

The contact between the sheet of gold and the sheet of iron allows a heat transfer until thermal equilibrium is done, which means that both sheets have the same temperature:

$-Q_{iron} = Q_{gold}$

$-(0.008\,kg)\cdot (452\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-54.4\,^{\textdegree}C) = (0.0195\,kg)\cdot (129\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-10.5\,^{\textdegree}C)$

$-(3.616\,\frac{J}{^{\textdegree}C})\cdot (T-54.4\,^{\textdegree}C) = (2.515\,\frac{J}{^{\textdegree}C})\cdot (T-10.5^{\textdegree}C)$

$-1.438\cdot (T - 54.4^{\textdegree}C) = T-10.5^{\textdegree}C$

$-1.438\cdot T +78.227^{\textdegree}C = T - 10.5^{\textdegree}C$

$2.438\cdot T = 88.727\,^{\textdegree}C$

The final temperature is:

$T = 36.393\,^{\textdegree}C$

8 0

2 years ago

Read 2 more answers

Which is the largest thing in the world???????????

Ksivusya [100]

<em>S</em><u><em>equoia trees</em></u> are the largest thing in the world or planet

thanx

<u>h</u><u><em>ope it helps you mark as brainlest</em></u>

5 0

3 years ago

Read 2 more answers

Using the following equation how many grams of water you would get from 886 g of glucose:

ankoles [38]

Answer:

531.6g

Explanation:

Total moles of glucose in this case is: 886/180= 4.922 (mole)

For every 1 mole glucose we get 6 mole water

-> Mole of water is: 4.922 * 6= 29.533 (mole)

weight of water is 18. Therefore, total weight of water that we will have from 886g of glucose are: 25.933*18= 531.6g

8 0

2 years ago

How many moles of NH3 can be produced from 12.0 mol of H2 and excess N2? Express your answer numerically in moles. View Availabl

VladimirAG [237]

Answer:

A) 8.00 mol NH₃

B) 137 g NH₃

C) 2.30 g H₂

D) 1.53 x 10²⁰ molecules NH₃

Explanation:

Let us consider the balanced equation:

N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)

Part A

3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:

$12.0molH_{2}.\frac{2molNH_{3}}{3molH_{2}} =8.00molNH_{3}$

Part B:

1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:

$4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}$

Part C:

According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:

$13.02gNH_{3}.\frac{6.00gH_{2}}{34.0gNH_{3}} =2.30gH_{2}$

Part D:

6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:

$7.62 \times 10^{-4} gH_{2}.\frac{2molNH_{3}}{6.00gH_{2}} .\frac{6.02\times 10^{23}moleculesNH_{3} }{1molNH_{3}}=1.53\times10^{20}moleculesNH_{3}$

3 0

3 years ago