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maxonik [38]
3 years ago
8

What is the definition of the change in free energy? AG=AH + TAS • AG=AH - TAS O AG = AHAS-T AG = AHAS + 1

Chemistry
1 answer:
svetoff [14.1K]3 years ago
4 0

Answer:

\Delta G=\Delta H-T\times \Delta S

Explanation:

The Gibbs free energy in thermodynamics is a potential which is used to calculate maximum of the reversible work which is performed by a specific thermodynamic system at constant temperature (isothermal) as well as pressure (isobaric).

The expression for the change in free energy is:

\Delta G=\Delta H-T\times \Delta S

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What is the total pressure of a container in kpa if the partial pressures are 1.25 atm and 66.7 psi?
STatiana [176]

Answer:

586 kpa(kilopascal/1000 pascals)

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given 1.24 atm(standard atmosphere), and 66.7 psi(pound force per square inch).

To find the total pressure we should use dalton's law of partial pressures which is the sum of the pressures of each individual gas.

then we convert them to pascals and divide by 1000 to get the measurement in kilopascal.

knowing that 1 atmosphere is proportional to around 14.696 psi. We can multiply our given measure of atm by that and sum it by psi like so. 1.24×14.6959 = 18.22298.

Then,

18.22298+ 66.7 = 84.92298

psi.

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4 0
3 years ago
A reaction that is second-order in one reactant has a rate constant of 1 × 10–2 L/mol · s. If the initial concentration of the r
Harlamova29_29 [7]

Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 1\times 10^{-2}mol/L.s

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.180 mol/L

[A]_o = Initial concentration = 0.360 mol/L

Putting values in above equation, we get:

1\times 10^{-2}=\frac{1}{t}\left (\frac{1}{0.180}-\frac{1}{0.360}\right)

t=277.8s

Hence, it take time for the concentration to become 0.180 mol/L will be, 277.8 s

7 0
3 years ago
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