A round bar of chromium steel, (ρ= 7833 kg/m, k =48.9 W/m-K, c =0.115 KJ/kg-K, α=3.91 ×10^-6 m^2/s) emerges from a heat treatmen
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Answer:
Carbon dioxide have higher temperature at the final stage.
Explanation:
Given that
We know that
γ=1.28 for carbon dioxide
γ=1.4 for air
For isentropic expansion
Now for carbon dioxide γ=1.28
Now for air γ=1.4
So carbon dioxide have higher temperature at the final stage.
Answer:
Explanation:
We will use the water property tables at respective states. Using Tables A-3, A-2, and A-5.
Part a
P = 10 bar and T = 179.9
From tables we find that the T saturated is also 179.9; Hence, the H20 exist in a two phase liquid-vapor mixture. T = [email protected]
For p-v and T-v see attachment 1
Part b
P = 10 bar and T = 150
From tables we find that the T saturated is 179.9; Hence, the H20 exist in the sub-cooled liquid region. T < [email protected]
For p-v and T-v see attachment 2
Part c
P = 0.5 bar and T = 100 C
From Temperature tables we find that the P saturated is 1.014 bar; Hence, the H20 exist in the super-heated region. P < [email protected] Table A-2
For p-v and T-v see attachment 3
Part d
P = 50 bar and T = 20 C
From Temperature tables we find that the P saturated is 0.02339 bar; Hence, the H20 exist in the sub-cooled liquid region. P > [email protected] Table A-2
For p-v and T-v see attachment 4
Part e
P = 1 bar and T = -6 C
From Temperature tables we find that the P saturated is 0.003689 bar; Hence, the H20 P > [email protected] solid because T is below triple point Temperature. Table A-5
For p-v and T-v see attachment 5
