1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
34kurt
3 years ago
12

Select the correct answer.

Engineering
1 answer:
steposvetlana [31]3 years ago
8 0

Answer: Technical sales engineer

Explanation:

An analysis engineer makes use of data and other technical information in order for him or her to be able to analyze a project plan, and provide necessary solutions.

Technical sales engineers gives their clients the needed support and sales advice for their business to thrive. Technical sales engineers helps their clients in giving technical advices, answering queries, as well as introducing new products.

Design engineers are the engineers that study, and develop ideas that will be used for new products. Sometimes, they also modify systems used in production so that organizational performance can be improved.

Inspection engineers are the engineers that looks at infrastructures and identify the problems affecting them e.g oil pipelines, roads, bridges, etc so that accidents will be prevented.

Consulting engineer is an engineer that deals with the planning, and infrastructures. Their work benefits the society as a whole.

Based on the above explanation, the answer is technical sales engineer.

You might be interested in
What is electromagnetic induction?
Over [174]
The process of using magnetic fields to produce voltage.
6 0
3 years ago
Steam enters a two-stage adiabatic turbine at 8 MPa and 5008C. It expands in the first stage to a state of 2 MPa and 3508C. Stea
Nataly [62]

Answer:

1) The exergy of destruction is approximately 456.93 kW

2) The reversible power output is approximately 5456.93 kW

Explanation:

1) The given parameters are;

P₁ = 8 MPa

T₁ = 500°C

From which we have;

s₁ = 6.727 kJ/(kg·K)

h₁ = 3399 kJ/kg

P₂ = 2 MPa

T₂ = 350°C

From which we have;

s₂ = 6.958 kJ/(kg·K)

h₂ = 3138 kJ/kg

P₃ = 2 MPa

T₃ = 500°C

From which we have;

s₃ = 7.434 kJ/(kg·K)

h₃ = 3468 kJ/kg

P₄ = 30 KPa

T₄ = 69.09 C (saturation temperature)

From which we have;

h₄ = h_{f4} + x₄×h_{fg} = 289.229 + 0.97*2335.32 = 2554.49 kJ/kg

s₄ =  s_{f4} + x₄×s_{fg} = 0.94394 + 0.97*6.8235 ≈ 7.563 kJ/(kg·K)

The exergy of destruction, \dot X_{dest}, is given as follows;

\dot X_{dest} = T₀ × \dot S_{gen} = T₀ × \dot m × (s₄ + s₂ - s₁ - s₃)

\dot X_{dest} = T₀ × \dot W×(s₄ + s₂ - s₁ - s₃)/(h₁ + h₃ - h₂ - h₄)

∴ \dot X_{dest} = 298.15 × 5000 × (7.563 + 6.958 - 6.727 - 7.434)/(3399 + 3468 - 3138  - 2554.49) ≈ 456.93 kW

The exergy of destruction ≈ 456.93 kW

2) The reversible power output, \dot W_{rev} = \dot W_{} + \dot X_{dest} ≈ 5000 + 456.93 kW = 5456.93 kW

The reversible power output ≈ 5456.93 kW.

6 0
3 years ago
Let f(t) be an arbitrary signal with bandwidth Ω. Determine the minimum sampling frequencies ωs needed to sample the following a
disa [49]

Answer:

See explaination

Explanation:

We can describr Aliasing as a false frequency which one get when ones sampling rate is less than twice the frequency of your measured signal.

please check attachment for the step by step solution of the given problem.

7 0
3 years ago
This assignment is designed to test your understanding of graphical user interface components and Event Driven programming in Ja
lys-0071 [83]

Answer:

Java program is given below

Explanation:

JavaPadGUI.java

package javapad.gui;

import java.awt.BorderLayout;

import java.awt.Container;

import java.awt.Dimension;

import java.awt.event.ActionEvent;

import java.awt.event.ActionListener;

import java.awt.event.WindowAdapter;

import java.awt.event.WindowEvent;

import java.io.File;

import java.io.FileNotFoundException;

import java.io.PrintWriter;

import java.util.Scanner;

import javax.swing.JButton;

import javax.swing.JFrame;

import javax.swing.JLabel;

import javax.swing.JOptionPane;

import javax.swing.JPanel;

import javax.swing.JScrollPane;

import javax.swing.JTextArea;

public class JavaPadGUI extends JFrame implements ActionListener{

  //constants

  private static final String TITLE = "Macrosoft JavaPad XP";

  private static final String SLOGAN = "Macrosoft: Resistance is futile";

 

  //button names

  private static final String NEW = "New";

  private static final String LOAD = "Load";

  private static final String SAVE = "Save";

  private static final String QUIT = "Quit";

 

  private static final String FILENAME = "hardcode.txt";

  //messages

 

  private static final String QUIT_MSG = "Quitting, Save?";

  private static final String LOAD_ERR = "Could not access file " + FILENAME;

 

 

  //fields

  private JTextArea txtContent;

  private JButton butNew, butLoad, butSave, butQuit;

 

  public JavaPadGUI()

  {

      super(TITLE);

      createUI();

      setSize(new Dimension(400, 300));

      setDefaultCloseOperation(EXIT_ON_CLOSE);

         

  }

 

  private void createUI()

  {

      Container c = getContentPane();

      c.setLayout(new BorderLayout(30,30));

     

      //create the buttons panel

      JPanel butPanel = new JPanel();

      butPanel.add(butNew = new JButton(NEW));

      butPanel.add(butLoad = new JButton(LOAD));

      butPanel.add(butSave = new JButton(SAVE));

      butPanel.add(butQuit = new JButton(QUIT));

     

      //set command names for the buttons, these will be when button is clicked

      butNew.setActionCommand(NEW);

      butLoad.setActionCommand(LOAD);

      butSave.setActionCommand(SAVE);

      butQuit.setActionCommand(QUIT);

     

      JPanel sloganPanel = new JPanel();

      sloganPanel.add(new JLabel(SLOGAN));

     

      //create textarea with scrollbar

      txtContent = new JTextArea(15, 25);

      txtContent.setLineWrap(true);

         

      JScrollPane scroll = new JScrollPane(txtContent);

     

      //now add all components

      c.add(butPanel, BorderLayout.NORTH);

      c.add(scroll, BorderLayout.CENTER);

      c.add(sloganPanel, BorderLayout.SOUTH);

     

     

      //set the actionlistner to buttons to handle button click event

      butNew.addActionListener(this);

      butLoad.addActionListener(this);

      butSave.addActionListener(this);

      butQuit.addActionListener(this);

     

  }

  public void actionPerformed(ActionEvent e)

  {

      String cmd = e.getActionCommand();

      if(cmd.equals(NEW))

          txtContent.setText("");

      else if (cmd.equals(LOAD))

          load();

      else if(cmd.equals(SAVE))

          save();

      else if (cmd.equals(QUIT))

          quit();

  }

  private void quit()

  {

      int option = JOptionPane.showConfirmDialog(this, QUIT_MSG);

      if(option == JOptionPane.YES_OPTION)

      {

          save();

      }

     

      System.exit(0);

  }

 

  private void save()

  {

      try {

          PrintWriter w = new PrintWriter(new File(FILENAME));

          w.write(txtContent.getText());

          w.close();

      } catch (FileNotFoundException e) {

          JOptionPane.showMessageDialog(this,"I/O Error", LOAD_ERR, JOptionPane.ERROR_MESSAGE);

      }

             

  }

  private void load()

  {

      try {

          Scanner s = new Scanner(new File(FILENAME));

          String str = "";

          while(s.hasNextLine())

              str += s.nextLine();

          txtContent.setText(str);

          s.close();

      } catch (FileNotFoundException e) {

          JOptionPane.showMessageDialog(this, LOAD_ERR, "I/O Error",JOptionPane.ERROR_MESSAGE);

      }

     

  }

}

RunJavaPad.java

package javapad;

import javapad.gui.JavaPadGUI;

public class RunJavaPad {

  public static void main(String[] args) {

      JavaPadGUI gui = new JavaPadGUI();

      gui.setVisible(true);

  }

}

7 0
3 years ago
A non-inductive load takes a current of 15A at 125V. An inductor is then connected in series in order that the same current shal
Norma-Jean [14]

Answer:

The inductance of the inductor is 0.051H

Explanation:

From Ohm's law;

  V = IR .................. 1

The inductor has its internal resistance referred to as the inductive reactance, X_{L}, which is the resistance to the flow of current through the inductor.

From equation 1;

V = IX_{L}

X_{L} = \frac{V}{I} ................ 2

Given that; V = 240V, f = 50Hz, \pi = \frac{22}{7}, I = 15A, so that;

From equation 2,

X_{L}= \frac{240}{15}

    = 16Ω

To determine the inductance of the inductor,

X_{L} = 2\pifL

L = \frac{X_{L} }{2 \pi f}

  = \frac{16}{2*\frac{22}{7}*50 }

 = 0.05091

The inductance of the inductor is 0.051H.

4 0
3 years ago
Other questions:
  • If link AB of the four-bar linkage has a constant counterclockwise angular velocity of 58 rad/s during an interval which include
    11·1 answer
  • For some transformation having kinetics that obey the Avrami equation , the parameter n is known to have a value of 1.1. If, aft
    6·1 answer
  • The pressure in an automobile tire depends on thetemperature of the air in the tire. When the air temperature is25°C, the pressu
    11·1 answer
  • The design for a new cementless hip implant is to be studied using an instrumented implant and a fixed simulated femur.
    11·1 answer
  • Carbon resistors often come as a brown cylinder with colored bands. These colored bands can be read to determine the manufacture
    7·1 answer
  • Given a program with execution times broken down shown below. Assume that techniques can only be applied to accelerate the integ
    12·1 answer
  • (100 POINTS) {BRIANLIEST} PLEASE HELP ME
    5·1 answer
  • When a company in the United States employs people in India to answer their customer service calls this is an example of
    9·1 answer
  • What two factors are changing when the current is changed on an electric generator
    7·1 answer
  • Technician A says the compressor is the dividing line of the refrigeration system, low- to high-side. Technician B says the expa
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!