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3 years ago

What is the empirical formula for propene C3H6

Chemistry

1 answer:

USPshnik [31]3 years ago

3 0

The empirical formula is the simplest formula attainable while maintaining the ratio so it will be CH2.

Explanation:

The empirical formula of a chemical compound is the simplistic positive integer ratio of atoms being in a compound. A simple example of this thought is that the empirical formula of sulfur monoxide, or SO, would simply be SO, as is the empirical formula of disulfur dioxide, S2O2.

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Alice and Marge are studying the properties of matter. The girls cut some silver-colored magnesium sheets into 3-inch long strip

frosja888 [35]

<span>B) Magnesium reacts in acids</span>

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ʕ•ᴥ•ʔ Which type of reaction occurs between an acid and a base and results in the formation of a salt and water? ʕ•ᴥ•ʔ

Nataliya [291]

The answer would be D. because when an acid and base mix the start to cancel each other out causing it to neutralize

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A sample of nitrogen gas, (N2), occupies 45.0 mL at 27.00∘C and 80.0 kPa. What will be the pressure if the gas is cooled to −73.

maxonik [38]

Answer:

The new pressure is 53.3 kPa

Explanation:

This problem can be solved by this law. when the volume remains constant, pressure changes directly proportional as the Aboslute T° is modified.

T° increase → Pressure increase

T° decrease → Pressure decrease

In this case, temperature was really decreased. So the pressure must be lower.

P₁ / T₁ = P₂ / T₂

80 kPa / 300K = P₂/200K

(80 kPa / 300K) . 200 K = P₂ → 53.3 kPa

6 0

3 years ago

A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction t

andreev551 [17]

Answer: The volume of the sample after the reaction takes place is 29.25 L.

Explanation:

The given reaction equation is as follows.

$OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)$

So, moles of product formed are calculated as follows.

$\frac{3}{2} \times 0.17 mol \\= 0.255 mol$

Hence, the given data is as follows.

$n_{1}$ = 0.17 mol, $n_{2}$ = 0.255 mol

$V_{1}$ = 19.5 L, $V_{2} = ?$

As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L$

Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

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2 years ago

How do scientists classify intrusive igneous features? according to shape, texture, and their distance from the nearest volcanic

Nataliya [291]

according to shape, size, and their relationship to surrounding layers of rock

Explanation:

Scientists classify intrusive features according to their shape, size and relationship to surrounding layers of rocks.

Intrusive igneous features are the sills, di/kes, batholith, laccoiith, lopolith e.t.c

When magma cools and solidifies within the earth crust, they form intrusive igneous rocks.
Intrusive igneous rocks differs from one another in their shape, size and relationship to surrounding rocks.
For example, batholith is a large intrusive body that extends for several kilometers in the earth surface.
Sills and di/kes are smaller bodies. Sills forms parallel to orientation of rocks in an area. Di/kes are known to cut across the orientation.

Learn more:

Sedimentary rocks brainly.com/question/2740663

#learnwithBrainly

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3 years ago