All categories

3 years ago

What is the molarity of solution that contains 5.80 grams of nickel nitrate,ni(no3)2 in 500.ml?

1 answer:

3 0

Molarity is defined as the number of moles of solute in 1 L of solution
molar mass of Ni(NO₃)₂ - 182.7 g/mol
number of moles of Ni(NO₃)₂ - 5.80 g/ 182.7 g/mol = 0.0317 mol
number of moles in 500 mL - 0.0317 mol
therefore number of moles in 1000 mL - 0.0317 mol / 500 mL x 1000 mL/L
molarity of the solution is - 0.0634 M

You might be interested in

The amount of energy stored in a molecule of ato compared to the amount stored in a molecule of glucose is

frozen [14]

Did you mean "atp"? if so It is less I hope this helps please mark brainliest :)

6 0

3 years ago

Which law is based on the graph that is shown below?

Cerrena [4.2K]

Answer:

Boyle's Law

Explanation:

8 0

3 years ago

Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mec

Svetach [21]

The overall reaction is given by:

$Br_{2}(g) + 2 NO(g) \rightarrow 2 NOBr(g)$

The fast step reaction is given as:

$NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})$

The slow step reaction is given as:

$NOBr_{2}(g) + NO(g) \rightarrow 2 NOBr(g)$ (slow step $k_{2}$ )

Now, the expression for the rate of reaction of fast reaction is:

$r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]$

The expression for the rate of reaction of slow reaction is:

$r_{2}=k_{2}[NOBr_{2}] [NO]$

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as $[NOBr_{2}]$ takes place in this reaction.

The expression of rate of formation is:

$\frac{d(NOBr)}{dt}=r_{2}$

= $k_{2}[NOBr_{2}][NO]$ (1)

Now, consider that the fast step is always is in equilibrium. Therefore, $r_{1}=0$

$k_{1}[NO][Br_{2}]= k_{-1}[NOBr_{2}]$

$[NOBr_{2}] = \frac{k_{1}}{k_{-1}}[NO][Br_{2}]$

Substitute the value of $[NOBr_{2}]$ in equation (1), we get:

$\frac{d(NOBr)}{dt}=k_{2}[NOBr_{2}][NO]$

= $k_{2} \frac{k_{1}}{k_{-1}}[NO][Br_{2}][NO]$

= $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$

Thus, rate law of formation of $NOBr$ in terms of reactants is given by $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$ .

4 0

3 years ago

A sample has a pH of -0.248 (yes, it really is possible to have a negative pH). Find

dalvyx [7]

Answer:

pOH= 14.248

[H+]=1.77 M

[OH-]=5.65 x10^-15M

Explanation:

pH+pOH= 14

pOH= 14-pH

pOH=14-(-0.248)

pOH= 14.248

[H+]=10^-pH= 10^-(-0.248)=1.77 M

[OH-]=10^-pOH= 10^-14.248=5.65 x10^-15M

5 0

3 years ago

You put two open cans of soda on the table. You took one can from the refrigerator and the other from your car. When you open th

jarptica [38.1K]

The soda can from the car will lose CO2 more quickly. This is because of the kinetic energy and behavior of gas molecules under different temperatures. CO2 is more soluble in cold temperatures than hot. Cold temperatures minimize the kinetic energy of gas molecules; thus, preventing the gas from escaping the soda. This is why soda that comes from the refrigerator has more fizz or spirit than soda at room temperature.

4 0

3 years ago